molecular equation, and net ionic equation of

Question

K2SO4 + MgCl2
NiCl2 + NaOH
MgCl2 + NaOH
K2SO4 + NaOH
Ba(OH)2 + NiCl2
Ba(OH)2 + MgCl2
Ba(OH)2 + K2SO4
Ba(OH)2 + NaOH
Na2CrO4 + Sr(NO3)2
Na2CrO4 + Al2(SO4)3
K2CrO4 + Sr(NO3)2
K2CrO4 + Al2(SO4)3
AgNO3 + BaCl2
AgNO3 + Na2CrO4
AgNO3 + Al2(SO4)3
AgNO3 + K2CrO4

Thank you! I really Appreciate it!

Answer 1

I will show you how to do one and then you can have a go at the others. First decide if the mixture will give you a reaction, a precipitate. If there is no reaction there is neither a molecular equation or a net ionic equation.

Start with the molecular formula

Na2CrO4(aq) + Sr(NO3)2(aq) -> NaNO3(aq) + SrCrO4(s)

balance the equation

Na2CrO4(aq) + Sr(NO3)2(aq) -> 2NaNO3(aq) + SrCrO4(s)

write in all the ions

2Na+(aq) + CrO4^2-(aq) + Sr^2(aq)+2NO3-(aq)->
2Na2+(aq)+ 2NO3-(aq) + SrCrO4(s)

now you delete ions that appear on each side, so you end up with

CrO4^2-(aq) + Sr^2(aq)->
SrCrO4(s)

which is the net ionic equation.

Answer 2

Mgcl+k2SO4