Asked by Anonymous
                molecular equation, and net ionic equation of
K2SO4 + MgCl2
NiCl2 + NaOH
MgCl2 + NaOH
K2SO4 + NaOH
Ba(OH)2 + NiCl2
Ba(OH)2 + MgCl2
Ba(OH)2 + K2SO4
Ba(OH)2 + NaOH
Na2CrO4 + Sr(NO3)2
Na2CrO4 + Al2(SO4)3
K2CrO4 + Sr(NO3)2
K2CrO4 + Al2(SO4)3
AgNO3 + BaCl2
AgNO3 + Na2CrO4
AgNO3 + Al2(SO4)3
AgNO3 + K2CrO4
Thank you! I really Appreciate it!
            
        K2SO4 + MgCl2
NiCl2 + NaOH
MgCl2 + NaOH
K2SO4 + NaOH
Ba(OH)2 + NiCl2
Ba(OH)2 + MgCl2
Ba(OH)2 + K2SO4
Ba(OH)2 + NaOH
Na2CrO4 + Sr(NO3)2
Na2CrO4 + Al2(SO4)3
K2CrO4 + Sr(NO3)2
K2CrO4 + Al2(SO4)3
AgNO3 + BaCl2
AgNO3 + Na2CrO4
AgNO3 + Al2(SO4)3
AgNO3 + K2CrO4
Thank you! I really Appreciate it!
Answers
                    Answered by
            Dr Russ
            
    I will show you how to do one and then you can have a go at the others. First decide if the mixture will give you a reaction, a precipitate.  If there is no reaction there is neither a molecular equation or a net ionic equation.
Start with the molecular formula
Na2CrO4(aq) + Sr(NO3)2(aq) -> NaNO3(aq) + SrCrO4(s)
balance the equation
Na2CrO4(aq) + Sr(NO3)2(aq) -> 2NaNO3(aq) + SrCrO4(s)
write in all the ions
2Na+(aq) + CrO4^2-(aq) + Sr^2(aq)+2NO3-(aq)->
2Na2+(aq)+ 2NO3-(aq) + SrCrO4(s)
now you delete ions that appear on each side, so you end up with
CrO4^2-(aq) + Sr^2(aq)->
SrCrO4(s)
which is the net ionic equation.
    
Start with the molecular formula
Na2CrO4(aq) + Sr(NO3)2(aq) -> NaNO3(aq) + SrCrO4(s)
balance the equation
Na2CrO4(aq) + Sr(NO3)2(aq) -> 2NaNO3(aq) + SrCrO4(s)
write in all the ions
2Na+(aq) + CrO4^2-(aq) + Sr^2(aq)+2NO3-(aq)->
2Na2+(aq)+ 2NO3-(aq) + SrCrO4(s)
now you delete ions that appear on each side, so you end up with
CrO4^2-(aq) + Sr^2(aq)->
SrCrO4(s)
which is the net ionic equation.
                    Answered by
            Robiya
            
    Mgcl+k2SO4
    
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