Asked by Queen
In order to make 500.0mL of a 1.835 M MgCl2 solution, then _______g of MgCl2 is needed.
Moles of MgCl2= (1.835M)(0.5L)=0.9175mol
Molecular Weight of MgCl2= 95.211 g/mol
(0.9175mol MgCl2)(95.211 g/mol)=
87.36g of MgCl2
Did I do this correct?
Moles of MgCl2= (1.835M)(0.5L)=0.9175mol
Molecular Weight of MgCl2= 95.211 g/mol
(0.9175mol MgCl2)(95.211 g/mol)=
87.36g of MgCl2
Did I do this correct?
Answers
Answered by
bobpursley
yes.
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