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In the formula 2C4H10+13O2=10H2O+8CO2 whats

  1. In the formula 2C4H10+13O2=10H2O+8CO2 whats the mass of butane needed to produce 79.7g of carbon dioxide.
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    2. Anonymous asked by Anonymous
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  2. How many grams of H2O (Mm = 18.0 g/mol) are produced in the combustion of 70.0 g of C4H10 (Mm = 58.1 g/mol)?2C4H10 + 13O2 8CO2 +
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    2. Anonymous asked by Anonymous
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  3. 2c4h10+13o2 8co2+10h2o how many moles of co2 is produced when 76.9g o2 is consumed when butane is burned
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    2. AP asked by AP
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  4. Calculate the mass of water produced when 3.09g of butane reacts with excess oxygen.2C4H10 + 13O2-->10H2O + 8CO2 Help.
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    2. Jennie asked by Jennie
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  5. Write the general rate equation for each of the components in the balanced equation for the combustion of butane2C4H10(g)+
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    2. Kristi asked by Kristi
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  6. Butane, , is a component of natural gas that is used as fuel for cigarette lighters.At 1.00 and 23 , how many liters of carbon
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    2. George asked by George
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  7. Butane, C4H10, is a component of natural gas that is used as fuel for cigarette lighters. The balanced equation of the complete
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    2. john asked by john
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  8. Butane, C4H10, is a component of natural gas that is used as fuel for cigarette lighters. The balanced equation of the complete
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    2. EM asked by EM
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  9. Butane, C4H10, is a component of natural gas that is used as fuel for cigarette lighters. The balanced equation of the complete
    1. answers icon 3 answers
    2. Amy asked by Amy
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  10. Butane, C4H10, is a component of natural gas that is used as fuel for cigarette lighters. The balanced equation of the complete
    1. answers icon 2 answers
    2. K asked by K
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