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In a dry cell, MnO2
In a dry cell, MnO2 occurs in a semisolid electrolyte paste and is reduced at the cathode. The MnO2 used in dry cells can itself
1 answer
asked by
Anusha
1,150 views
In a dry cell, MnO2 occurs in a semisolid electrolyte paste and is reduced at the cathode. The MnO2 used in dry cells can itself
1 answer
asked by
Mel
1,247 views
When combined with cupric ions (aq, 1M) which will produce the largest standard cell voltage? (Use data from table 20.1, and
1 answer
asked by
mandeep
1,459 views
Consider the reaction MnO2+4HCL===>MnCl2+Cl2+2H2O
How many grams of MnO2 are required to produce 5.6 of Cl2 at stp?MnO2=87
1 answer
asked by
faisal
944 views
The electrochemical cell described by the cell notation has a standard emf (electromotive force) of -0.68 V. Calculate the value
8 answers
asked by
me
790 views
MnO4^-(aq) + H20(l) ==> MnO2 + OH^-
net charg is -1 +7 (-8) ==> 4(-4) Manganese is reduced MnO4^- +3e- ==> MnO2 H2) is the
2 answers
asked by
Steve
1,418 views
The electrochemical cell described by the balanced chemical equation has a standard emf of -0.25 V. Calculate the value (kJ) for
1 answer
asked by
Jess
659 views
MnO2(s) -> MnO(s) + 1/2O2(g) Delta H1 = +32.5 kcal
MnO2(s) + Mn(s) -> 2MnO(s) Delta H2 = -59.0 kcal Calculate Delta H final of
0 answers
asked by
Lisa
794 views
Pt(s) | Mn2+(aq), MnO4-(aq), H+(aq) || H+(aq), IO3-(aq) | I2(s) | Pt(s)
Pt(s) | Mn2+(aq) | MnO2(s) | H+(aq) || H+(aq) || PbO2(s)
3 answers
asked by
eng
982 views
Given the following data:
MnO(s) + H2(g) Mn(s) + H2O(l), H = 100 kJ MnO2(s) + 2 H2(g) Mn(s) + 2 H2O(l), H = –52 kJ use
1 answer
asked by
Ari
1,671 views