Asked by faisal
Consider the reaction MnO2+4HCL===>MnCl2+Cl2+2H2O
How many grams of MnO2 are required to produce 5.6 of Cl2 at stp?MnO2=87
How many grams of MnO2 are required to produce 5.6 of Cl2 at stp?MnO2=87
Answers
Answered by
DrBob222
5.6 what? L?
You have the balanced equation.
Convert 5.6 L to mols at STP.
Use the coefficients to convert mols Cl2 to mols MnO2.
Then g MnO2 = mols x molar mass.
You have the balanced equation.
Convert 5.6 L to mols at STP.
Use the coefficients to convert mols Cl2 to mols MnO2.
Then g MnO2 = mols x molar mass.
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