MnO2(s) -> MnO(s) + 1/2O2(g) Delta H1 = +32.5 kcal

Question

MnO2(s) + Mn(s) -> 2MnO(s) Delta H2 = -59.0 kcal

Calculate Delta H final of MnO2 in KJ.

The answer is not as important to me as the explanation. So, can someone please show me how to do this type of a problem?