Asked by Jess
The electrochemical cell described by the balanced chemical equation has a standard emf of -0.25 V. Calculate the value (kJ) for the ΔG˚ of the cell. Round your answer to 3 significant figures.
MnO2(s) + Pb2+(aq) → Mn2+(aq) + PbO2(s)
St. Red. Pot. (V)
PbO2/Pb2+ +1.46
MnO2/Mn2+ +1.21
Faraday's Constant
F = 96485 C
MnO2(s) + Pb2+(aq) → Mn2+(aq) + PbO2(s)
St. Red. Pot. (V)
PbO2/Pb2+ +1.46
MnO2/Mn2+ +1.21
Faraday's Constant
F = 96485 C
Answers
Answered by
DrBob222
DG<sup>o</sup> = -nE<sup>o</sup>F
Substitute and solve for DG<sup>o</sup>
Substitute and solve for DG<sup>o</sup>
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