Ask a New Question
Search
Bond enthalpy is the energy
Bond enthalpy is the energy required to break a mole of a certain type of bond.
O=O = 495 kj/mol S-F = 327 kj/mol S=O = 523
1 answer
asked by
Dr BOB plz ANSWER
812 views
Bond enthalpy is the energy required to break a mole of a certain type of bond.
O=O = 495 kj/mol S-F = 327 kj/mol S=O = 523
0 answers
asked by
kira
1,034 views
Bond enthalpy is the energy required to break a mole of a certain type of bond.
O=O = 495 kj/mol S-F = 327 kj/mol S=O = 523
0 answers
asked by
dereyab
681 views
The enthalpy of dissociation for hydrogen
H2(g) → 2 H(g) is ΔH = 436.0 kJ/mol. What is the difference between the bond
0 answers
asked by
LaurenB
608 views
Consider the hypothetical elements X and Y. Suppose the enthalpy of formation for the compound XY is -336 kJ/mol, the bond
2 answers
asked by
Jude
931 views
Consider the hypothetical elements X and Y. Suppose the enthalpy of formation for the compound XY is ƒ{336 kJ/mol, the bond
1 answer
asked by
chemistry
829 views
Using the form of energy diagram,make a concept map of the two different methods of calculation of reaction enthalpy(via the
1 answer
asked by
Gift
1,094 views
Use the table below to calculate the change in enthalpy (bond energy) for the reaction above.
Bond Type Bond Energy kJ/mol O - H
1 answer
26 views
Use the table below to calculate the change in enthalpy (bond energy) for the reaction above.
Bond Type Bond Energy kJ/mol
1 answer
35 views
The average bond enthalpy for C__H is 413 kJ/mol. In other words, 413 kJ of energy is required to break a mole of CH into atoms:
0 answers
asked by
sarah
1,133 views