Asked by sarah
The average bond enthalpy for C__H is 413 kJ/mol. In other words, 413 kJ of energy is required to break a mole of CH into atoms:
CH (g) ----> C(g) + H(g) delta H= 413 kJ
Using this information, and enthalpy of C6H6=5535kJ, calculate the enthalpy change of the reaction:
C6H6 (g) --> 6CH (g)
CH (g) ----> C(g) + H(g) delta H= 413 kJ
Using this information, and enthalpy of C6H6=5535kJ, calculate the enthalpy change of the reaction:
C6H6 (g) --> 6CH (g)