Ask a New Question

Asked by Dr BOB plz ANSWER

Bond enthalpy is the energy required to break a mole of a certain type of bond.

O=O = 495 kj/mol
S-F = 327 kj/mol
S=O = 523 kj/mol


Use average bond enthalpies to estimate the enthalpy delta H (rxn) of the following reaction:

2SF4 + O2 ---- 2OSF4

Express your answer numerically in kilojoules.


is answer 103 KJ
16 years ago

Answers

Answered by DrBob222
answered below.
16 years ago

Related Questions

The average bond enthalpy for a C=C double bond is 614kj/mol and that of a C-C single bond is 348kj/... The bond enthalpy of N2(g) is 418.0 kJ/mol. Calculate ÄH°f for N(g). I figured that if it gave th... "Given that the bond enthalpy of the carbon-oxygen bonds in carbon monoxide and carbon dioxide are 1... The bond enthalpy of N2(g) is 418.0 kJ/mol. Calculate ÄH°f for N(g).? The bond enthalpy of F2(g) is 156.9 kJ/mol. Calculate ÄH°f for F(g). 1 kJ/mol The O−H bond enthalpy is 463 kJ/mol. What is the wavelength of light that will cause dissociation... The bond enthalpy of the Br−Cl bond is equal to ƒ¢H‹ for the reaction BrCl(g) ¨ Br(g) + Cl(g).... What is the bond enthalpy of N2(g)+2H2(g) --> N2H4(g)? Use the molar bond enthalpy data in the table to estimate the value of Δ𝐻∘rxn for the equation...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use