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An equilibrium mixture of PCl5(g),

PCl5 dissociates according to the reaction: PCl5(g) ↔ PCl3(g) + Cl2(g). One mole of PCl5 was placed in one liter of solution.
1. 2 answers
2. asked by Sam
3. 3,414 views
At 25C, an equilibrium mixture of gases con- tains 0.00680 mol/L PCl3, 0.0290 mol/L Cl2, and 0.00500 mol/L PCl5.PCl5(g) ⇀ ↽
1. 2 answers
2. asked by Sara
3. 560 views
When a sample of PCl5(g) (0.02087 mol/L) is placed in 83.00 L reaction vessel at 491.0 °C and allowed to come to equilibrium
1. 3 answers
2. asked by Drew
3. 1,181 views
The equilibrium constant, K, for the following reaction is 1.54×10-2 at 506 K:PCl5(g) PCl3(g) + Cl2(g) An equilibrium mixture
1. 0 answers
2. asked by Daniel
3. 615 views
Equilibrium Equation with Partial Pressures PCl3(g) +Cl2(g) <-> PCl5(g)?An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g)
1. 8 answers
2. asked by Kylie
3. 1,761 views
Pure PCL5 is introduced into an evacuated chamber and comes to equilibrium at 247C and 2 atm. The equilibrium gaseous mixture
1. 2 answers
2. asked by how
3. 2,514 views
Consider the following equilibrium:PCl5 = PCl3+ Cl2 5.0 moles of are placed in a 10.0 L flask at 200 C and allowed to come to
1. 2 answers
2. asked by AMI
3. 1,006 views
Given the equilibrium system PCL5(g) <----->PCl3(g) + Cl2(g)K = 12.5 at 60 degrees celsius. A 1.0 L reaction vessel is analyzed
1. 1 answer
2. asked by ChemMaster98
3. 804 views
Given the equilibrium system PCl5(g) <---> PCl3(g) + Cl2(g)K = 12.5 at 60 degrees Celsius. A 1.0-L reaction vessel is analyzed
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2. asked by Walter
3. 698 views
At 760◦C, Kc= 33.3 for the reaction PCl5(g)⇀↽PCl3(g) + Cl2(g) If a mixture that consists of 0.31 mol PCl3 and 0.22 mol Cl2
1. 1 answer
2. asked by Melody
3. 1,343 views