Asked by Sam
PCl5 dissociates according to the reaction: PCl5(g) ↔ PCl3(g) + Cl2(g). One mole of PCl5 was placed in one liter of solution. When equilibrium was established, 0.5 mole of PCl5 remained in the mixture. What is the equilibrium constant for this reaction?
Answers
Answered by
DrBob222
............PCl5 ==> PCl3 + Cl2
initial......1.0M......0......0
change.......-x.......x.......x
equil.......1-x.......x.......x
The problem tells you that 1-x = 0.5; therefore, x = 1.0-0.5= 0.5M which means Pl3 = 0.5M and Cl2 = 0.50M
Then K = (PCl3)(Cl2)/(PCl5) \
Substitute and solve for K.
initial......1.0M......0......0
change.......-x.......x.......x
equil.......1-x.......x.......x
The problem tells you that 1-x = 0.5; therefore, x = 1.0-0.5= 0.5M which means Pl3 = 0.5M and Cl2 = 0.50M
Then K = (PCl3)(Cl2)/(PCl5) \
Substitute and solve for K.
Answered by
Sam
thank you
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