Asked by alexa
sulfur trioxide gas dissociates into sulfer dioxide gas and oxygen gas at 1250 degrees C. In an experiment, 3.6 moles of sulfur trioxide were placed into an evacuated 3.0-L flask. THe concentration of sulfur dioxide gas measured at equilibrium was found to be 0.20 M. What is the equilibrium constant, Kc, for the reaction?
SO3 ==> SO2 + O2
(SO3) = 3.6 mols/3.0 L = 1.2 M initially.
(SO2) = 0.2 M at equilibrium.
(O2) = 0.2 M at equilibrium.
(SO3) = 1.2-0.2 = 1.0 M
Plug into Kc and calculate.
SO3 ==> SO2 + O2
(SO3) = 3.6 mols/3.0 L = 1.2 M initially.
(SO2) = 0.2 M at equilibrium.
(O2) = 0.2 M at equilibrium.
(SO3) = 1.2-0.2 = 1.0 M
Plug into Kc and calculate.
Answers
Answered by
Anonymous
1.6 x 10^-2
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