Asked by lauren
Ammonium iodide dissociates reversibly to ammonia and hydrogen iodide.
NH4I(s) Picture NH3(g) + HI(g)
At 400°C, Kp = 0.215. Calculate the partial pressure of ammonia at equilibrium when a sufficient quantity of ammonium iodide is heated to 400°C.
NH4I(s) Picture NH3(g) + HI(g)
At 400°C, Kp = 0.215. Calculate the partial pressure of ammonia at equilibrium when a sufficient quantity of ammonium iodide is heated to 400°C.
Answers
Answered by
DrBob222
What's with the picture stuff? Just put an arrow there.
NH4I(s) ==> NH3(g) + HI(g)
.............p..........p
Kp = pNH3*pHI = 0.215 (what? atm?)
Substitute into Kp and solve for p.
NH4I(s) ==> NH3(g) + HI(g)
.............p..........p
Kp = pNH3*pHI = 0.215 (what? atm?)
Substitute into Kp and solve for p.
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