50 g x 0.459 = g Ag
50 g x (1.000-0.459) = g I or 1/2 that of I2.
urgent
50 g x (1.000-0.459) = g I or 1/2 that of I2.
50.0g*(1.00-0.450)= 27.05g I
50= (22.95)+(27.05)
Silver= 22.95g
Given:
- Mass of silver iodide sample = 50 g
- Silver iodide is 45.9% silver by mass
Step 1: Calculate the mass of silver in the sample.
Mass of silver = 45.9% * 50 g = 0.459 * 50 g = 22.95 g
Step 2: Calculate the mass of iodide in the sample.
Since we know the sample's mass is 50 g, we can subtract the mass of silver from the total mass to find the mass of iodide.
Mass of iodide = Total mass - Mass of silver = 50 g - 22.95 g = 27.05 g
Therefore, in the 50-g sample of silver iodide, you would have:
- 27.05 g of iodide
- 22.95 g of silver
Given that silver iodide is 45.9% silver by mass, this means that for every 100 grams of silver iodide, it contains 45.9 grams of silver.
To find the amount of iodide in the 50-g sample, we subtract the mass of silver from the total mass of the sample. Given that silver iodide is 45.9% silver, it means that the remaining 54.1% is iodide. So, we can calculate the mass of iodide as follows:
Mass of iodide = Total mass of sample × Percentage of iodide
Mass of iodide = 50 g × (54.1/100) = 27.05 g
Therefore, in the 50-g sample of silver iodide, you would have 27.05 grams of iodide and the remaining mass of silver, which is:
Mass of silver = Total mass of sample - Mass of iodide
Mass of silver = 50 g - 27.05 g = 22.95 g
Hence, you would have 27.05 grams of iodide and 22.95 grams of silver in the 50-g sample of silver iodide.