Asked by Sara

At 25C, an equilibrium mixture of gases con- tains 0.00680 mol/L PCl3, 0.0290 mol/L Cl2, and 0.00500 mol/L PCl5.
PCl5(g) ⇀ ↽ PCl3(g) + Cl2(g)
What is the equilibrium constant for the reaction?
How would I do this? I'm so confused!
Answered by DrBob222
There isn't anything here to be confused about.
............PCl5 --> PCl3 + Cl2
E.........0.00500..0.00680..0.0290

What's K.
Kc = (PCl3)(Cl2)/(PCl5)
Plug in the equilibrium numbers and solve for Kc.
Answered by Sara
So I disregard the temperature?
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