AMI

Consider the following equilibrium: PCl5 = PCl3+ Cl2 5.0 moles of are placed in a 10.0 L flask at 200 C and allowed to come to equilibrium. Analysis shows that 1.0 mole of is present in the equilibrium mixture. How many moles of are present at equilibrium...

For the system 2A (g) + B( g) = 2C (g), if the initial concentration of pure C is 1.00 M, the equilibrium concentration is 0.40 M. What is the value of Kc? Choose one answer. a. 5.0 b. 0.45 c. 0.67 d. 2.2 e. 1.5

Consider the following equilibrium: PCl3 + Cl2 = PCl5 Kc=26 @ 250 degree Celcius 1.0 mol of PCl3 , 1.0 mol of Cl2 , and 5.0 mol of PCl5 are placed in a 10.0L flask at 250 C and allowed to come to equilibrium. What is the concentration, in M, of at equilib...

At a particular temperature, Kc = 54 for the reaction H2(g) + I2 (g) <=> 2 HI(g). One mole of HI is placed in a 3.0-L container. What would be the equilibrium concentration of HI? Choose one answer. a. 0.035 b. 0.071 c. 0.29 d. 0.30 e. 0.33

Given the initial concentrations of 0.10 atm NO2 and 0.10 atm N2O4 in a 1.0 L flask, what will be the equilibrium partial pressure of NO2? N2O4(g)=2NO2 Kp=0.660at319K Choose one answer. a. 0.10 atm b. 0.31 atm c. 0.045 atm d. 0.72 atm e. 0.19 atm

Ka for hypochlorous acid,HCLO, IS 3.0*10^-8. Calculate the pH after 10.0,20.0,30.0, and 40.0mL OF 0.100M NaOH have been added to 40.0mL of 0.100M HCLO..

Calculate the [NH4+] in solution that is 0.25 M NH3 and 0.20 M NaOH. (Kb for NH3 = 1.8 x 10-5) I set up ICE from the equation: NH3 + H20 ------NH4 + OH- I 0.25 0 0 C -x +x +x E 0.25-x x x 1.8 *10^-5 = x*x/ 0.25-x 4.5* 10^-6 = x2 took the square root to ge...

Calcaulate the pH after 10.0 mL of 0.40 M HCl is added to 20.0 mL of 0.50 M NaOH. I wasn't sure on how to start this problem. I tried to break the HCl and NaOH apart then I set up ICE for each but I did get the wrong answer of 13.70. a. 0.40 b. 13.70 c. 1...

What molarity of a NH4NO3 solution has a pH of 5.220? Kb for NH3 is 1.8 x 10^-5. Choose one answer. a. 6.31x 10-6. b. 2.21 x 10-6 c. 5.56x 10-10. d. 0.065 I started by taking the inverse log of the PH to get (6.02*10^-6) then I was thinking its not the wa...

Calculate the vapor pressure at 25 C of hexane above the solution. The vapor pressure of pure hexane at 25 C is 151 torr. A solution contains naphthalene ({\rm{C}}_{10} {\rm{H}}_8) dissolved in hexane ({\rm{C}}_6 {\rm{H}}_{14}) at a concentration of 12.17...

I HAVE $100.00 THE GST IS 10% THEREFORE TO GET THE GST PORTION I DO THE FOLLOWING: 100/11=9.09 NOW I HAVE $100.00 THE GST IS 15% THEREFORE 100/? =13.04

Thanks I figured out what I didn't do which was factor in that 0.2M of NAOH

I get 0 as the answer but not sure if I am right

2A + B= 2C I 0 0 1.00 C 2X X -2X E 2X X 1.00-2X KC= 0.40= C^2/ A^2*B square root 0.40 (x*x)=1.00-2x 0.40(X)^2 SQUARE ROOT 0.40-1.00 I ended up with 0.09 but when I plugged it back in then I don't get any of the above answers. I don't know what I was doing...

Consider the following equilibrium: PCl3 + Cl2 = PCl5 Kc=26 @ 250 degree Celcius 1.0 mol of PCl3 , 1.0 mol of Cl2 , and 5.0 mol of PCl5 are placed in a 10.0L flask at 250 C and allowed to come to equilibrium. What is the concentration, in M, of Cl2 at equ...

PCL5(g)=PCL3(g)+CL2(g) 5.0 moles of PCL5 are placed in a 10.0 L flask at 200 C and allowed to come to equilibrium. Analysis shows that 1.0 mole of is present in the equilibrium mixture. How many moles of Cl2 are present at equilibrium. Choose one answer....

(a) Calculate the acceleration of the system. (b) Calculate the force that each crate exerts on the other (c) Repeat with the crates reversed. fIND ACCELERATION AND CRATE FORCE.