2cos*2x-cosx=1 find all solutions to

  1. Verify the identity:tanx(cos2x) = sin2x - tanx Left Side = (sinx/cosx)(2cos^2 x -1) =sinx(2cos^2 x - 1)/cosx Right Side = 2sinx
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    2. Ashley asked by Ashley
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  2. Please help!!!!!!!!!!! Find all solutions to the equation in the interval [0,2π).8. cos2x=cosx 10. 2cos^2x+cosx=cos2x Solve
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    2. Anonymous asked by Anonymous
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  3. 2cos*2x-cosx=1 find all solutions to the equation on the domain [0,2ð]i got ð/4, 7ð/4, 3ð/4, and 5ð/4 but only got two out
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    2. Kindell asked by Kindell
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  4. Find all solutions of the equation in the interval [0,2pi)2 cos^2 x-cos x = 0 -2cos^2 + cosx + 0 (x+1/2) (x+0/2) (2x+1) (x+0)
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    2. Anonymous asked by Anonymous
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  5. solve 2cos^2x = square root of three cosx (couldnt find the sign on keyboard sorry) for principal values of x. express the
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    2. Kathy asked by Kathy
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  6. prove the identity(sinX)^6 +(cosX)^6= 1 - 3(sinX)^2 (cosX)^2 sinX^6= sinx^2 ^3 = (1-cosX^2)^3 = (1-2CosX^2 + cos^4) (1-cosX^2)
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    2. JungJung asked by JungJung
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  7. Approximate the equation's solutions in the interval (0,2pi)sin2x sinx = cosx 2cos(x) (1/2-sin^2x) = 0 Then I got 3pi/2, pi/2,
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    2. Abbey asked by Abbey
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  8. solve for 0=/<x<2pi6sin^2x + sinx - 1 = 0 Ahh, forgot how to factor. 3cos^2 - 2cos - 1 = 0 (3cosx + 1 )(cosx - 1) cosx= -1/3, 1
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    2. sh asked by sh
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  9. Which of the following are trigonometric identities?(Can be more then one answer) tanx cosx cscx = 1 secx-cosx/secs=sin^2x
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    2. Jill asked by Jill
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  10. tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
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    2. shan asked by shan
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