Ask a New Question

2KI+Pb(NO3)2=2KNO3+PbI2 suppose a solution containing

2KI+Pb(NO3)2=2KNO3+PbI2suppose a solution containing 1.25g of KI is combined with a solution containing 2.42g Pb(NO3)2 _what
1. 1 answer
2. asked by may
3. 1,457 views
Considering the following precip reactionPb(NO3)2(aq)+2KI(aq)----->PbI2(s)+2KNO3(aq) What is the correct net ionic equation? I
1. 0 answers
2. asked by STAT
3. 1,135 views
Given this equation:2KI + Pb(NO3)2 ---> PbI2 + 2KNO3 calculate mass of PbI2 produced by reacting of 30.0 g KI with excess
1. 1 answer
2. asked by mya
3. 386 views
20.0 mL of a 0.125 M solution of potassium iodide is added to 15.0 mL of a 0.235 M solution of lead (II) nitrate. A reaction
1. 2 answers
2. asked by Brunette
3. 612 views
4. In the balanced reaction Pb(NO3)2+2KI=PbI2+2KNO3 what is the ratio of potassium iodide (KI) to lead iodide (PbI2)?A. 3:1 B.
1. 1 answer
2. asked by answersss
3. 52 views
A student reacted 0.500g of Pb(NO3)2 with 0.750g of KI according to the reaction,Pb(NO3)2(aq) + 2KI(aq)=PbI2(s) + 2KNO3(aq) A)
1. 2 answers
2. asked by Gina
3. 3,049 views
Why does a clear, saturated solution of PbI2 form a yellow precipitate when a small amount of KI is added to the solution?A. KI
1. 4 answers
2. asked by Laura
3. 2,917 views
A 25.00 mL sample of a clear saturated solution of PbI2 requires 14.3 mL of a certain AgNO3(aq) for its titration.I^-(from satd
1. 2 answers
2. asked by Ash
3. 1,421 views
Lead(II) nitrate solution reacts with potassium iodide solution to produce lead(II) iodide and potassium nitrate.The answer in
1. 1 answer
2. asked by Jeff
3. 1,777 views
For the reaction: Pb(NO3)2 (aq) + 2 NaI (aq)→ PbI2 (s) + 2 NaNO3 (aq)a. How many grams of PbI2 will be formed from 25.0 mL of
1. 1 answer
2. asked by Carmen
3. 148 views