2KI+Pb(NO3)2=2KNO3+PbI2 suppose a solution containing

  1. 2KI+Pb(NO3)2=2KNO3+PbI2suppose a solution containing 1.25g of KI is combined with a solution containing 2.42g Pb(NO3)2 _what
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    2. may asked by may
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  2. Considering the following precip reactionPb(NO3)2(aq)+2KI(aq)----->PbI2(s)+2KNO3(aq) What is the correct net ionic equation? I
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    2. STAT asked by STAT
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  3. Given this equation:2KI + Pb(NO3)2 ---> PbI2 + 2KNO3 calculate mass of PbI2 produced by reacting of 30.0 g KI with excess
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    2. mya asked by mya
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  4. 20.0 mL of a 0.125 M solution of potassium iodide is added to 15.0 mL of a 0.235 M solution of lead (II) nitrate. A reaction
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    2. Brunette asked by Brunette
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  5. 4. In the balanced reaction Pb(NO3)2+2KI=PbI2+2KNO3 what is the ratio of potassium iodide (KI) to lead iodide (PbI2)?A. 3:1 B.
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    2. answersss asked by answersss
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  6. A student reacted 0.500g of Pb(NO3)2 with 0.750g of KI according to the reaction,Pb(NO3)2(aq) + 2KI(aq)=PbI2(s) + 2KNO3(aq) A)
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    2. Gina asked by Gina
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  7. Why does a clear, saturated solution of PbI2 form a yellow precipitate when a small amount of KI is added to the solution?A. KI
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    2. Laura asked by Laura
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  8. A 25.00 mL sample of a clear saturated solution of PbI2 requires 14.3 mL of a certain AgNO3(aq) for its titration.I^-(from satd
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    2. Ash asked by Ash
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  9. Lead(II) nitrate solution reacts with potassium iodide solution to produce lead(II) iodide and potassium nitrate.The answer in
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    2. Jeff asked by Jeff
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  10. For the reaction: Pb(NO3)2 (aq) + 2 NaI (aq)→ PbI2 (s) + 2 NaNO3 (aq)a. How many grams of PbI2 will be formed from 25.0 mL of
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    2. Carmen asked by Carmen
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