Answers by visitors named: Jeff
It's been years since I read the book but wasn't Johnny cleared of charges in the book? Wasn't it ruled that he acted in self-defence?
What is the question?
Im really unsure about this question i have not been taught this type of graphing before. It is a tough one.
1) Did not give enough power to the federal government
2) No national currency
Gave 2/3 majority of the 13 colonies.
elevation
also apply the rules of divisibility
Thanks so much. I've been struggling with that thing for days!
Ooo ok thanks so much, I got it :D
oops it didn't write the question like i wanted it to, here I'll fix it
4x/x^2-9 - 5x/x^2+4x-+3
I'm not sure, but my answer would be 15. you multiply 18x4=72, 9x3=27, 3x2=6 add them together, it makes 105 divided by 3x2+1=7, so 105 divided by 7=15.
I hope it helps
I think it's "B"
Thanks
thank you
This is helpful, thanks Christine
is Hf triangleH'f?? and if so would the value be -285.83?
for b, would we want the specific heat of h2o (l) or (s)?
I have this exact same question, but in my assignment I'm told I have to make a table of values, graph whatever it is, find the x&y intercepts, find the domain and range, determine whether it's increasing or decreasing, the equation of the asymptote, and what is the implication of the asymptote related to caffeine in the body.
* disregard the caffeine comment. sorry about that.
wouldn't the answer be 1?
Would (2,1) (3,5) and (4,9) work as well? Thanks!
Even though you switched it to the y = 4x - 7? Is this all the same or is the -7 and 7 the constants changed? Thanks
So which is the correct method? Switching the original, or just using variables as i did to make the equation true
4x-y = 7
4(2) - 1 = 7 (2,1)
4(3) - 5 = 7 (3,5)
4(4) - 9 = 7 (4,9)
Which method is correct? Or does it not matter because the equation has infinate solutions? Thanks!
Lingual describes speech sounds formed with the tongue
Are you a math teacher? Just wondering?
That makes sense..High School?
Ok! Have a good night and thanks for the help!
Mixing the two is simply and acid base reaction.
CH3COOH + NaHCO3 ---> CH3COONa + H2CO3
That last product is carbonic acid which quickly decomposes into
carbon dioxide and water:
H2CO3 ---> H2O + CO2
The CO2 is what you see foaming and bubbling in this reaction.
relating to the biting surface of a molar or premolar tooth
i googled leepa rattner musuem, and it's under galleries. thanks.
The answers 1559 right??
(a) What is the initial velocity of the green car?
(b) What is the acceleration of the green car?
Sorry I forgot to post the actual questions.
Yes I know of using that equation but the acceleration is not constant so I can't just plug in into an equation with a different x value.
If you plug in x=1, you find that f(x)=4x^3-36x^2+96x-64 evaluates to zero. From here, use either synthetic division or long division to get the quadratic 4x^2-32x+64. Reduce to x^2-8x+16 and solve by factoring into (x-4)^2.
So 4x^3-36x^2+96x-64=4(x-1)(x-4)^2.
I got the the LineScrabble class:
import java.io.*;
public class LineScrabble extends Echo{
int max = 0;
String bestLine = "";
public LineScrabble(String f) throws IOException
{
super(f);
}
int[] scrabbles = {1,3,3,2,1,4,2,4,1,8,5,1,3,1,1,3,10,1,1,1,1,4,4,8,4,10};
public void processLine(String s)
{
s.toLowerCase();
int score = 0;
for(int i = 0; i<s.length(); i++){
int w = (int)(s.charAt(i)-97);
if (w >=0 && w <= 25)
{
if (i == 0)
{
score += 2*scrabbles[w];
}
else if (i%4==0 && i%9==0)
{
score += 2*scrabbles[w];
}
else if (i%9==0)
{
score += 3*scrabbles[w];
}
else if (i%4==0)
{
score += 2*scrabbles[w];
}
}
System.out.println(score);
}
if(score > max)
{
max = score;
bestLine = s;
}
}
public void results()
{
System.out.println("Winning score: " + max);
System.out.println("Winning line: " + bestLine);
}
}
7.90%
51.4
902 mL
a) Given total cost function as C=160+16Q+0.1Q(2){squared} and price equation P=96-0.4Q.
Total Revenue function is R=PQ=96Q-0.4Q(2).
The profit function is F=R-C=(96Q-0.4Q(2))-(160+16Q+0.1Q(2))=80Q-0.5Q(2)-160.
Profit attains maximum when and is negative dF/dQ=0 and d(2)F/dQ(2) is negative.
dF/dQ(fraction)=0 -> 80-Q= 0 -> Q=80
d(2)F/dQ(2) (fraction)= -1
Now it is clear that profit attains maximum when Q = 80
Price when Q = 80 is P=96-0.4*80=64
The profit-maximizing price = 64 and quantity = 80
Maximum Profit = [80Q-0.5Q(2)-160]Q=80(subscript) = 3040
b) The average cost function is AC = C/Q= 160/Q{fraction}+16+0.1Q
The AC function attains minimum when dAC/dQ {fraction}=0 and d(2)AC/dQ(2){fraction} is positive
dAC/dq{fraction}=0 -> -160/q(2){fraction} +0.1=0 -> -160+0.1Q(2)=0
i.e., Q(2) -1600=0 -> (q+40)(Q-40)=0 -> 40 or -40
Since Q cannot be negative Q = 40
d(2)AC/dQ(2){fraction}=320/Q(3){fraction}
Clearly d(2)AC/dQ(2){fraction} is positive when Q = 40
It is clear that the firms average cost of production is minimized at an output of 40 units.
The firm’s production manager’s first claim is the firm’s average cost of production is minimized at an output of 40 units, is correct.
But, her second claim, the firms’ profit maximizing level of output is 40 units, is not correct.
Note that from (a) we got the firms’ profit maximizing level of output is 80 units.
When Q = 40 the firms profit is (F=80*40-0.5*40(2)-160) = 2240,
But, when Q = 80 we got profit = 3040
c) If the firm uses a second plant with costs identical to the first. Then the cost function becomes C=320+32Q+0.2Q(2).
But, the demand function remains the same; unfortunately the revenue function remains unchanged. i.e.,R=PQ=96Q-0.4Q(2).
Now the new profit function becomes
F=R-C=96Q-0.4Q(2))-(320+32Q+0.2Q(2))=64Q-0.6Q(2)-320
dF/dQ{fraction}=0 -> 64-1.2Q= 0->Q=53.33
d(2)F/dQ(2){fraction}=-1.2
That is profit attains maximum when Q = 53.33
The maximum profit is[64Q-0.6Q(2)-320]Q=53.33{subscript} = 1386.67
So the firm cannot increase its profit by adding a second plant.
The conc is 6.0M HCL
Volts divided by the amount of resistance will give you the amps.
a) west
b) zero deflection
c) up
d) down
I think you would need one of the variables because all that is telling me is 180 = 1/2bh .
Are there any other variables listed?
I found the same problem in my son's math homework when he learned LCM. That's maybe why my son used LCM to solve it.
I used similar way to Reiny's.
i.e.
Nick's speed: 1/8.
Isah's speed : 1/10.
When Nick passed Isah for the second time, Nick will run 1 more mile than Isah. so the time should be:
1/(1/8-1/10)=40 minutes.
the author of this problem assumed that he passed him at the same place
Sorry, whenever I post, the pattern does not come out right. There should be one "I" diagonally down and to the right and one to the left of B. Same pattern with all the other letters. Thanks
Yes.
X=2-2t
y=3t
Around the town of Gettysburg, Pennsylvania...
I know how to make soap, using lye. I want to be able to make the lye solution from wood ash be the same ph as commercial lye. I think this can be done using the ph of sodium hydroxide in water as I first stated. Is it possible to compute this ph.
I need to duplicate the strength of lye made from wood ash dissolved in water (Potassium Hydroxide) to that of lye made from Sodium Hydroxide disolved in water. The soap recipes I use require lye of various strengths as determined by fluid volume of water combined with the prescribed humber of grams of sodium hydroxide. e.g. 6 fluid oz of water combined with 58 g of sodium hydroxide. This makes lye of a specific strength. I want to be able to duplicate the strength of the sodium hydroxide lye water when useing potassium hydroxide made from dissolving wood ash in water. I can make the potassium hydroxide lye water stronger by reducing its volume with heat or weaker by increasing its volume by adding more water. I assume the easiest way to make potassium hydroxide lye water of the same strength as the sodium hydroxide lye water is to make them have the same PH. To do this I need to know the PH of a solution made from 6 fluid oz of water combined with 58 gr of sodium hydroxide.
Not sure that you need that dash in "already-significant"
In the end, change "help" to "helping."
Better yet, you could say "I'm looking forward to contributing to the success of your company."
sqrt(55)-sqrt(1/55)+sqrt(5/11)=?
6. A right circular cylinder is to be designed to hold 750 cm3 of processed milk, and to use a minimal amount of material in its construction. Find the dimensions for the container.
A right circular cylinder is to be designed to hold 750 cm3 of processed milk, and to use a minimal amount of material in its construction. Find the dimensions for the container.
What is it?
It does not have anything by the cc.
First of all your initial vertical velocity is not 4.5 m/s.
it is Viy= 4.5 * sin(30)
and your horizontal = 4.5 * cos(30)
Ms. Sue, no offense, but stop making assumptions you can't justify. How do you know it's a wild-guess answer?
That's insulting their intelligence.
Did you get this answer???
how do you solve for v ?
thank you !
Cod+ H20 <==> HCod+ OH-
0.002M x M x M
0.002-x +x +x
Kb=(HCod)(OH)/(Cod)=x^2/(0.002-x)
8.33x 10^-7=x^2/(0.002-x)
x=4.08x 10^-5 (theres [HCod])
pOH= PKb + log (HB/B-)
pOH= -log(8.33x 10^-7) + log(4.08x10^-5/0.002) = 4.38
POH + pH = 14 : 14- pOH = pH
14-4.38=
9.62
16
Write an algebraic rule to describe the relationship in each table
It changed my theta sign to the è. But those are supposed to be theta.
If this is a physics question it might be that you should lose mass. Weight can change with location (weight is just the measure of gravity's pull) but mass does not.
Since it's just a line, make an x y table of values, plot the points, and connect them with a line. Or you could use transformation rules by moving around the graph of y=x.
Dave your dealing with Circular motion so you would use this circular motion formula;Ac=Vc2/r
1. In your problem your trying to find the radius.
2. The Ac is already given, but since the problem asks for it not to exceed 6.15 times the free-fall acceleration. You must times them.
Ac=6.15*9.81
Ac=~60.3315m/s.
3. Next, you plug in your airplane speed (104m/s.) and square that.
4. Your final step is to divide 104(squared) by 6.15*9.81.
Giving you the answer of ~179.276m.
Good Luck! With the rest of your Physics!
We know the formula for the Volume of a Right Circular Cone is given by
V=(1/3)*pi*r^2*h
V=140 in^3
The height of the cone = diameter of the base. The diameter = 2 times the radius, so h = 2r
The formula for Volume can now be written as
V=(1/3)*pi*r^2*(2r)
which simplifies to
V=(2/3)*pi*r^3
You plug in 140 in^3 for V and solve for r. Then you can plug the value you find for r into the equation h=2r
Sharon swims 1/4 of the total route
Swim = (1/4)*TotRoute
Sharon cycles 3/5 of the remaining route
Cycles = (3/5)*(3/4)*TotRoute
Notice the 3/4. If she swam 1/4 of the total route, 3/4 of the route remains for cycling and running.
Sharon runs rest of the route
Runs = (2/5)*(3/4)*TotRoute = 3,600 meters
2/5 of the remaining route is what is left after the 3/5 of the remaining route of cycling
Solve the Runs equation first
3,600 meters = (6/20)*TotRoute
Solve for TotRoute
The answer is TotRoute = 12,000 meters
You can also solve for swim and cycle if you wish. Plug back into the other equations
Swim = (1/4)*TotRoute = (1/4)*12,000 meters = 3,000 meters
Cycles = (3/5)*(3/4)*TotRoute = (3/5)*(3/4)*12,000 meters = 5,400 meters
Could Answer c be 160 cm^3 and not 16 cm^3?
The answer would then be C. 160 cm^3
The Volume of a cone is given by
V=(1/3)*pi*r^2*h
We know V= 540 cm^3 and that r=15 cm and can plug into the equation to find h.
I am going to leave the units off, but you should include it in your work.
540=(1/3)*pi*(15)^2*h
Solving for h gives
h=2.292 cm
Now a similar cone will have the same ratio
h1/r1 = h2/r2
(2.292 / 15) = (h2 / 10) and solve for h2.
h2 = 1.528 cm
Throw this into the Volume of a cone
V=(1/3)*pi*r^2*h
V=(1/3)*pi*(10)^2*(1.528) = 160 cm^3
She could actualy do it several different combinations.
5 quarters, 1 dime, and 10 nickels
4 quarters, 5 dimes, and 7 nickels
3 quarters, 9 dimes, and 4 nickels
2 quarters, 13 dimes, and 1 nickel
You did the problem correctly. I am not sure how exactly you entered the numbers into the computer for pi, but it looks like with an answer of 24,523.71 the computer used an approzimation for pi based on the fraction 22/7.
22/7 = 3.142857....
If you plug the 22/7 instead of 3.14 you will get what the computer gets...
BAD is correct. It is 84. If you would like to use algebra, do the following:
x:= Unit Digit Number
y:= Tens Digit Number
The units digit is 4 less than the tens digit number so We know that
x=y-4
The tens digit is twice the units digit so we know that
y=2x
Now we can take the 1st equation and substitue into the second equation, then solve for Y.
y=2x
y=2(y-4)
y=2y-8
8=y so y=8
Now, sub this back into the 1st equation
x=y-4=8-4=4
so the number is yx = 84.
Reiny, Agreed, but that is what it appears to be using. I am guessing it was a software program and not the actual computer using that approximation.
What really irks me about pi is that most people know it is 3.1415....., but have NO idea what it actually represents....
BTW Cassie, please please always remember that pi is simply a circle's circumference divided by it's diameter. For every circle, no matter the size...
This is why it shows up in so many formulas for circles, cylinders, cones, etc.
Convert the 9m of cloth to cm = 900 cm to start with.
She has 90 cm of cloth left so she used
900 cm - 90 cm = 810 cm of cloth
Let X = cloth for tablecloth
Let 2X = cloth for each cushion cover.
The equation would be:
810 = X + 4 * 2x
810 = X + 8X
810 = 9X
X=90cm
2X=2(90cm) = 180 cm
So the tablecloth = 90 cm, and each cushion cover is 180 cm.
$38.40 = (1-0.40)* Price
Price = $38.40 = $64.00
-------
0.6
Just wanted to say thanx for the help Bob
If X^2-5 is the denom, then the domain would be all X such that the denom does not equal 0.
So find when x^2-5=0
x=sqrt(5) (Both positive and negative)
So the domain is all real numbers, such that X does not equal +- sqrt (5)
Robby if you need more help,type ur question ino the search bar on your computor and a site titled chap15 fd.valenciacollege.edu will come up and it will break down complete indtructions on how to go about figuring out this question.I hope this helps.
Yes, you are correct.
Key word is circular, so we are talking about a circle. pi = circumference of a circle / diameter --> pi = C / d
Solve for C
C = pi*d = (3.14) *(10 ft) = 31.4 ft, assuming the approximation of 3.14 for pi.
Think of a right triangle. The airport is the vertex of the right angle. Plane A is 70 miles north (Straight up). Plane B is 168 miles East (Straight right). From plane A to B would be side C of the right triange.
C^2 = A^2 + B^2
C = sqrt (A^2 + B^2)
C = sqrt (70^2 + 168^2)
C = sqrt (33124)
C = 182 miles
No, look at your answer... Your length is 4 times as long as your width... How did you come up with your answer?
1. Multiply out
z^2 + 6z + 14z^2 + 84z + 45 = 0
2. Combine like terms
15z^2 + 90z + 45 = 0
3. Use quadratic equation to get both answers for z.
2X + 1 r 2/(x-3)
No...Use c^2=a^2+b^2.
Use a= 24, b= 32 and c= 42 (the longest side).
Take a^2 + b^2 and see if it eqauls c^2
If it does, it is a right angle. If it does not, it is not a right triange.
In this case, it does not, so it is not a right triangle.
Keep in mind it does not have to be in ratio of 3:4:5 to be a right triangle, it has to make the equation c^2=a^2+b^2 true. Another common right triangle is 5,12,13.
Solve equation for Y
2x + 8y = 6
8y = 6 - 2x
y = 3/4 - x/4
Since this is a straight line, we can pick any value for X. Let's say X=2
Then y(2) = 3/4 - 2/4 = 1/4
Now, decrease x by 2, so x=0
y(0) = 3/4 - 0/4 = 3/4
The difference between Y(0) and Y(2) is
3/4 - 1/4 = 2/4 = 1/2
So the corresponding change in y is +1/2
Change 1.9 hours into a form we can use.
Let's break it into two parts. We know 1 hour is easy enough, and that will change the time to 4:05 PM (Subtract 1 hour from 5:05 PM).
For the 0.9 hour part, let's change this to minutes.
(0.9 hours)*(60 min / 1 hr) = 54 minutes.
Since we are at 4:05 PM, subtract 5 of the 54 min and we are at 4:00 PM and now need to subtract the remaining 49min, which 3:11 PM.
So 5:05 PM subtracting 1.9 hours is 3:11 PM. They key to this problem is getting the 1.9 hours into something we can use, and to break the large problem into smaller, managable problems.
Combine the like terms
(6a^4b - 6a^4b) + (ab^3 + 3ab^3)
= 0a^4b + 4ab^3
= 4ab^3
What are the internal angles required to make a pentagon with 36 millimetre sides?
Cheating is not allowed. HRP258
Hey Damon,
Part b and c:
(b) What is the force exerted by the wall on the ruler when it is at an angle θ=30∘? Express your answer as the x component Fx and the y component Fy (in Newton)
Fx=
Fy=
(c) At what angle θ0 will the falling ruler lose contact with the wall? (0≤θ0≤90∘; in degrees) [hint: the ruler loses contact with the wall when the force exerted by the wall on the ruler vanishes.]
θ0=
Can you show me the work to get these answers also?
2.Use the function,
f(x)=3x^2-16x+5/(3x-1)(x+4)^2:
a. Find the domain of f(x) in interval notation
b. Factor and simplify f(x) completely.
c. Find the x-intercept(s), if any.
d. Find the y-intercept, if any.
e. Determine the vertical asymptote(s), if any.
f. Determine the horizontal asymptote, if any.
bw,
For the above question (the block of mass 3kg one) I am still getting the incorrect answer for your answer of c.) 44.99
Is it possible this is incorrect still?
You beauty, Thanks bw.
All I have left is the falling ruler if you have any advice for that one. Otherwise thanks a million!
3. At the Constitutional Convention in Philadelphia, Madison drafted the plan presented by Virginia Governor Randolph, and William Patterson of _______ presented a plan that was similar to the Articles of Confederation.
A. Pennsylvania
B. South Carolina
C. Massachusetts
D. New Jersey
Hi. I don't understand why you multiply by 50*pi/180. The 50 degrees is the difference in the longitude, but why isn't that divided by 360? Why the pi/180? If someone could clear that up I would appreciate it.
Sorry, never mind. I figured it out.
Find an equation of the line that satisfies the given conditions
Through (-2,4); slope -1