Question
A 25.00 mL sample of a clear saturated solution of PbI2 requires 14.3 mL of a certain AgNO3(aq) for its titration.
I^-(from satd PbI2)+ Ag^+(from AgNO3)= AgI(s)
So, this is where I am.
using the Ksp equation for PbI2:
7.1*10^-9=4x^3
solving for x gives me 0.00121
Giving the concentration for I = 0.00242mol/L
Times this by 25ml gives me moles...
This is where I'm stuck
I^-(from satd PbI2)+ Ag^+(from AgNO3)= AgI(s)
So, this is where I am.
using the Ksp equation for PbI2:
7.1*10^-9=4x^3
solving for x gives me 0.00121
Giving the concentration for I = 0.00242mol/L
Times this by 25ml gives me moles...
This is where I'm stuck
Answers
Sorry the question is What is the molarity of this AgNO3(aq)?
Never mind I got it, just divide by the other ml amount :)
Related Questions
A 30.00mL sample of a clear saturated solution of PbI2 requires 14.7mL of a certain AgNO3 for its ti...
A solution of PbI2 has [Pb2+] = 4.5 x 10-5 and [I-] = 6.5 x 10-4. PbI2 has Ksp = 8.7 x 10-9. Write d...
A saturated solution is prepared by adding excess PbI2(s) to distilled water to form 1.0L of solutio...
Why does a clear, saturated solution of PbI2 form a yellow precipitate when a small amount of KI is...