Question
Not clear about this, please help me understand the steps:
(5b^2c^1/4)^3
(5b^2c^1/4)^3
Answers
MathMate
Apply the laws of exponents:
Laws of exponents:
x<sup>a</sup>*x<sup>b</sup> = x<sup>a+b</sup>
x<sup>a</sup>/x<sup>b</sup> = x<sup>a-b</sup>
<b>(x<sup>a</sup>)<sup>b</sup> = x<sup>ab</sup></b>
x<sup>-a</sup> = 1/x<sup>a</sup>
(5b^2c^1/4)^3
=5³ (b^2)³ (c<sup>1/4</sup>)³
=125 * b<sup>2*3</sup> c<sup>(1/4)*3</sup>
=125b<sup>6</sup> c<sup>3/4</sup>
Laws of exponents:
x<sup>a</sup>*x<sup>b</sup> = x<sup>a+b</sup>
x<sup>a</sup>/x<sup>b</sup> = x<sup>a-b</sup>
<b>(x<sup>a</sup>)<sup>b</sup> = x<sup>ab</sup></b>
x<sup>-a</sup> = 1/x<sup>a</sup>
(5b^2c^1/4)^3
=5³ (b^2)³ (c<sup>1/4</sup>)³
=125 * b<sup>2*3</sup> c<sup>(1/4)*3</sup>
=125b<sup>6</sup> c<sup>3/4</sup>