1. (sec^2x-6tanx+7/sec^2x-5)=(tanx-4/tanx+2) 2. (sin^3A+cos^3A/sinA+cosA)=1-sinAcosA 3.

1. (sec^2x-6tanx+7/sec^2x-5)=(tanx-4/tanx+2)2. (sin^3A+cos^3A/sinA+cosA)=1-sinAcosA 3. csc^6x-cot^6x+1+3csc^2xcot^2x please help
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2. asked by George
3. 794 views
Hello I am having trouble with proving this:sinA/secA+secA/cscA = tan(A)(2-sin^2(A)) So far I've gotten SinA/(1/cosA) +
1. 1 answer
2. asked by Jimbo
3. 828 views
For this question, they want me to use fundamental trig identities to simplify the expression. The problem is as follows;
1. 5 answers
2. asked by CodyJinks
3. 796 views
Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx.I don't know what i'm supposed to
1. 1 answer
2. asked by Marrion
3. 720 views
Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx.I don't know what i'm supposed to
1. 0 answers
2. asked by Marrion
3. 722 views
2tan^2x-tanx-1=00<x<2pi •MATH - Steve, Thursday, July 18, 2013 at 11:48am (2tanx+1)(tanx-1) = 0 tanx = -1/2 or 1 ... Recall in
1. 5 answers
2. asked by ROBIN
3. 625 views
Hi, can someone give me the answer to this question:secA-tanA=1/4. Find cosA I got: CosA=4(1-sinA) Is my answer good? Now
1. 2 answers
2. asked by Shym
3. 968 views
Perform the addition or subtraction.tanx - sec^2x/tanx tan^2(x)/tan(x) - sec^2x/tanx = tan^2x sec^2x / tanx then I use the
1. 1 answer
2. asked by Hannah
3. 808 views
how do you do sinAcosA=cosA-cos^3A/sinA
1. 2 answers
2. asked by PLEASE HELP!!!
3. 946 views
Derivative of y=sec(tanx)?I don't get how it is secxsecx*secxtanx*tanxtanx. Where does an extra tanx come from? Derivative of
1. 1 answer
2. asked by Beth
3. 792 views