Asked by Jimbo
Hello I am having trouble with proving this:
sinA/secA+secA/cscA = tan(A)(2-sin^2(A))
So far I've gotten
SinA/(1/cosA) + (1/cosA)/(1/sinA)
SinACosA + sinA/cosA
I am stuck here, not even sure if multiplying by the reciprocal was the right step..
sinA/secA+secA/cscA = tan(A)(2-sin^2(A))
So far I've gotten
SinA/(1/cosA) + (1/cosA)/(1/sinA)
SinACosA + sinA/cosA
I am stuck here, not even sure if multiplying by the reciprocal was the right step..
Answers
Answered by
Damon
on right
tan(A)(2-sin^2(A))
(sinA/cosA) (1 + cos^2A) because s^2+c^2 = 1
sinA / cosA + sinAcosA
looks like what you had on the left :)
tan(A)(2-sin^2(A))
(sinA/cosA) (1 + cos^2A) because s^2+c^2 = 1
sinA / cosA + sinAcosA
looks like what you had on the left :)