Question

I am having trouble with a pre-cal problem. If you could explain how to do it that would be great!
((3^3)^(cosx+2/3sinx))^2cosx+3sinx all divided by ((3^sinx)^13)^cosx = x

Answer 1

I do not follow your order of exponents
You will have to be much more specific by using brackets

e.g.
2^3^4
done on my calculator by punching it in that way
gives me 4096
(The calculator appears to evaluate from left to right and simply does (2^3)^4 = 2^12= 4096

But, what about
(2^(3^{^4})
= 2^81
= huge !

on calculator , enter

2
y^x
(
3
y^x
4
)
=
to one humongous number (2.41... x 10^24)

Please clean up your expression