Asked by ROBIN
2tan^2x-tanx-1=0
0<x<2pi
•MATH - Steve, Thursday, July 18, 2013 at 11:48am
(2tanx+1)(tanx-1) = 0
tanx = -1/2 or 1
...
Recall in which quadrants tanx is positive or negative
....................would x= 5pi/6,11pi/6,pi/4 and 5pi/4???
0<x<2pi
•MATH - Steve, Thursday, July 18, 2013 at 11:48am
(2tanx+1)(tanx-1) = 0
tanx = -1/2 or 1
...
Recall in which quadrants tanx is positive or negative
....................would x= 5pi/6,11pi/6,pi/4 and 5pi/4???
Answers
Answered by
Steve
no, arctan(1/2) = .46
so, x = pi+.46 or 2pi-.46
the pi/4 and 5pi/4 are correct
(arcsin(1/2) = pi/6, not arctan(1/2))
so, x = pi+.46 or 2pi-.46
the pi/4 and 5pi/4 are correct
(arcsin(1/2) = pi/6, not arctan(1/2))
Answered by
Reiny
small typo, I am sure Steve meant to type
x = <b>π - .46</b> or 2π-.46 , since the tan is negative in II and IV
x = <b>π - .46</b> or 2π-.46 , since the tan is negative in II and IV
Answered by
Steve
Good catch - what was I thinking?
But then, I'm sure Robin knew that...
But then, I'm sure Robin knew that...
Answered by
ROBIN
in radians what would the .46 be?
Answered by
Reiny
That IS in radians.
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