Asked by ROBIN

2tan^2x-tanx-1=0
0<x<2pi

•MATH - Steve, Thursday, July 18, 2013 at 11:48am
(2tanx+1)(tanx-1) = 0
tanx = -1/2 or 1
...
Recall in which quadrants tanx is positive or negative

....................would x= 5pi/6,11pi/6,pi/4 and 5pi/4???
Answered by Steve
no, arctan(1/2) = .46
so, x = pi+.46 or 2pi-.46

the pi/4 and 5pi/4 are correct

(arcsin(1/2) = pi/6, not arctan(1/2))
Answered by Reiny
small typo, I am sure Steve meant to type

x = <b>π - .46</b> or 2π-.46 , since the tan is negative in II and IV
Answered by Steve
Good catch - what was I thinking?
But then, I'm sure Robin knew that...
Answered by ROBIN
in radians what would the .46 be?
Answered by Reiny
That IS in radians.
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