Asked by Anonymous
Prove:
(tanx)(sinx) / (tanx) + (sinx) = (tanx) - (sinx) / (tanx)(sinx)
What I have so far:
L.S.
= (sinx / cosx) sinx / (sinx / cosx) + sinx
= (sin^2x / cosx) / (sinx + (sinx) (cosx) / cosx)
= (sin^2x / cosx) / (cosx / sinx + sinxcosx)
(tanx)(sinx) / (tanx) + (sinx) = (tanx) - (sinx) / (tanx)(sinx)
What I have so far:
L.S.
= (sinx / cosx) sinx / (sinx / cosx) + sinx
= (sin^2x / cosx) / (sinx + (sinx) (cosx) / cosx)
= (sin^2x / cosx) / (cosx / sinx + sinxcosx)
Answers
Answered by
Reiny
your equation is not an identity the way you wrote it,
try substituting any angle into the equation, it will not satisfy the equation.
The way you wrote it,
LS reduces to simply 2sinx
use brackets to identify the exact order of operation.
try substituting any angle into the equation, it will not satisfy the equation.
The way you wrote it,
LS reduces to simply 2sinx
use brackets to identify the exact order of operation.
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