Asked by Aliya
Prove that (secx+tanx)^2=1+sinx/1-sinx
Thanks in advance.
Thanks in advance.
Answers
Answered by
drwls
(secx + tanx)^2 = [(1 + sinx)/cosx]^2
= [1 + sinx]^2/[1 - sin^2x]
= (1 + sinx)(1 + sinx)/[(1 + sinx)(1-sinx)]
= (1+sinx)/(1-sinx)
= [1 + sinx]^2/[1 - sin^2x]
= (1 + sinx)(1 + sinx)/[(1 + sinx)(1-sinx)]
= (1+sinx)/(1-sinx)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.