0.222g of a divalents metal

  1. 0.222g of a divalents metal is deposited when a current of 0.45a is passed through a solution of it salts for 25mins calculate
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    2. catherine zechariah asked by catherine zechariah
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  2. 0.222g of a divalent metal is deposited when a current of 0.45A is passed through a solution of its salt for 15min. Calculate
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    2. Grace Bitrus asked by Grace Bitrus
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  3. 0.222g of a divalent metal is deposited when a current of 0.45ampere is passed through a solution of salt for 25min. Calculate
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    2. Anonymous asked by Anonymous
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  4. 0.222g of a divalent metal is deposited when a current of 0.45ampere is passed through a solution of its salt for 25min using
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    2. favour asked by favour
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  5. 0.222g of a divalent metal is deposited when a current of 0.45A is passed through a solution of its sent for 25mins. Calc the
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    2. Chioma asked by Chioma
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  6. 0.222g of a divalent metal is deposited when a current of 0.45A is pass through a solution of it's salt for 25 minutes calculate
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  7. 0.222g Of A Divalent Metal Is Deposited When A Current Of 0.45 Amperes Is Passed Through A Solution Of It's Salt For 25 Minutes
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    2. Franklin asked by Franklin
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  8. 0.222g of a divalent metal is deposited when a current of 0.4amperes is passed through a solution of it's salt for 25minutes
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    2. Douebi asked by Douebi
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  9. solution for the equation 0.222g of a divalent metal is deposited when a current of 0.45 ampere is passed through a solution of
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    2. maria ekere asked by maria ekere
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  10. A synthesis yielded 222g of phosphoric acid. How many moles of phosphoric acid were produced?I keep dividing 222g/98g (molar
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    2. Raeann asked by Raeann
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