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Answers (27)
yes
m=100kg h=60m t=20s p=? p=work \time =f×d\time =mg×h\t =100×10×60\20= 3000
i will lime to learn more on how to solve equations
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i need help in answering this question for me and show working
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Yes
is this correct
wow this was brain warming
pls, i need your answer
Thank you
You are very correct, i concur with your answer neiga
how to make fullness
no
notine
when he stands between the walls at a point equidistant from them. x=vt 330*6=1980
when he stands between the walls at a point equidistance from them
not f\weight
f/mg =45\25*10=45/250=0.18
not correct
2000pi cm2per minute
IF:- F=450N, M=50kg, & V=1.5m/s to find *Friction, *Power, & *Acceleration if the applied force increases to 500N :-friction=applied force/normal force =f/450, f=mgsin€, =50*10sin€=300 :-friction=450/300=1.5 power=work/time, workdone=mg :-50*10=500
Total mass:-121kg Acceleration:-1.20 Force:-? :-Using formula F=MA whe have:-121*1.20=145.2Ans to Check:-F=MA making A subject formula we have:- A=F/M which gives us 145.2/121=1.20 :-The Total mass 121kg with the acceleration 1.20 will need a total force
Total mass:-121kg Acceleration:-1.20 Force:-? :-Using formula we have F=MA F=121*1.20=145.2Ans to check:-F=MA :-making a subject of formula A=F/M 145.2/121=1.20 :-The total mass 121kg with acceleration 1.20 will need a force of 145.2
using F=MA, Mg=Mgsin in Relation we have;- M=20kg, F=40N, a=? :-(a) as subject formula, :- a=f/m, 40/20=2 mgsin= 2*10sin, 20sin30degree 10.
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