Asked by Douebi
0.222g of a divalent metal is deposited when a current of 0.4amperes is passed through a solution of it's salt for 25minutes calculate?
(I) time taken in seconds
(ii) quantity of electricity flowing
(iii) Atomic mass of the metal
(I) time taken in seconds
(ii) quantity of electricity flowing
(iii) Atomic mass of the metal
Answers
Answered by
DrBob222
time = 25 minutes x (60 sec/min) = 1500 seconds.
coulombs electricity = C = current x seconds = 0.4 amperes x 1500 sec = 600.0
96,485 coulombs will deposit (atomic mass/2) = 0.222 grams.
(atomic msss/2) x (600/96,485) = 0.222
atomic mass = 2*96,485*0.222/600 = 71.4 amu
Is this a made up problem. I don't see an atom with an atomic mass of 71.4 in the periodic table. Ge and Ga come the closest but not quite right. Ge is 72.6 and Ga is 69.7 BUT NEITHER IS DIVALENT. Gotta believe it's a made up problem.
coulombs electricity = C = current x seconds = 0.4 amperes x 1500 sec = 600.0
96,485 coulombs will deposit (atomic mass/2) = 0.222 grams.
(atomic msss/2) x (600/96,485) = 0.222
atomic mass = 2*96,485*0.222/600 = 71.4 amu
Is this a made up problem. I don't see an atom with an atomic mass of 71.4 in the periodic table. Ge and Ga come the closest but not quite right. Ge is 72.6 and Ga is 69.7 BUT NEITHER IS DIVALENT. Gotta believe it's a made up problem.
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