Question
0.22gg of divalent metal is deposited when a current of 0.45a is passed thought a solution of 25 min.calculate the ran of the metal
Answers
DrBob222
Coulombs = amperes x seconds = 0.45 amp x 25 min x (60 sec/min) = 675 C
96,485 coulombs will deposit atomic mass/2 grams of metal
eqivalent weight = 0.22 = atomic mass/2
675/96,485 = 0.006996
0.44/0.006996 = 62.89 or
(675/96,485) x atomic mass/2 = 0.22 g
Solve for atomic mass = 62.89
96,485 coulombs will deposit atomic mass/2 grams of metal
eqivalent weight = 0.22 = atomic mass/2
675/96,485 = 0.006996
0.44/0.006996 = 62.89 or
(675/96,485) x atomic mass/2 = 0.22 g
Solve for atomic mass = 62.89