v = Vi + a t
0 = 14.5 - 2.2 t
t = 14.5/2.2
t = 6.59 s
next get the distance
x = Xi + Vi t + (1/2) a t^2
x = 0 + 14.5(6.59) - 1.1(6.59)^2
= 95.6 - 47.8 = 47.8 meters
wow, half a football field !
With an average acceleration of −2.2 m/s^2,
how long will it take a cyclist to bring a bicycle
with an initial speed of 14.5 m/s to a complete
stop?
Answer in units of s.
1 answer
1 answer