how long does it take for v to drop to zero?
v(t) = 14.27 - 1.67t
using that t, the distance moved is
s(t) = 14.27t - 0.835t^2
A cyclist is coasting up a hill. At t=0, the cyclist has a velocity of 14.27 m/s. If the acceleration of
the cyclist is constant at -1.67 m/s2, how long will it take the cyclist to come to a complete stop? If the
peak of the hill is 40 m away from the cyclist at t=0, will she have to pedal to reach the top?
1 answer
0 answers