(a) time = velocity / acceleration
(b) distance = average velocity * stopping time
... average velocity = initial velocity / 2 ... final velocity is zero
(c) doubling the speed will double the average velocity
... it will also double the stopping time
... so the stopping distance is quadrupled
With an average acceleration of –0.5 m/s2, (a) how long will it take a cyclist to bring a bicycle with an initial velocity of +13.5 m/s to a complete stop? (b) Calculate the distance required for the bicyclist to come to rest. (c) If the cyclist’s initial speed is doubled to 27 m/s under the same condition, calculate the distance required for the cyclist to come to a halt.
1 answer
1 answer