What is the rate of the reaction:

H2SeO3 + 6I- + 4H+ Se + 2I3- + 3H2O

given that the rate law for the reaction at 0°C is
rate = (5.0 × 10^5 L5mol-5s-1)[H2SeO3][I-]^3[H+]^2

The reactant concentrations are [H2SeO3] = 1.5 × 10^-2 M, [I-] = 2.4 × 10^-3 M, [H+] = 1.5 × 10^-3 M.

1 answer

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