Estimate the rate of the reaction,

Question

H2SeO3 + 6I- + 4H+ Se + 2I3- + 3H2O

given that the rate law for the reaction at 0°C is
rate = (5.0 × 10^5 L5mol-5s-1)[H2SeO3][I-]^3[H+]^2

The reactant concentrations are [H2SeO3] = 1.5 × 10^-2 M, [I-] = 2.4 × 10^-3 M, [H+] = 1.5 × 10^-3 M.

My answer:
Rate = (5.0 × 10^5 L5mol-5s-1)(1.5 × 10^-2 M) (2.4 × 10^-3 M)^3 (1.5 × 10^-3 M)^2

Rate = 2.33 x 10^-10

Answer 1

rate if reaction =12