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Estimate the rate of the reaction,

H2SeO3 + 6I^- + 4H^+ --> Se + 2I3^- + 3H2O

given that the rate law for the reaction at 0°C is
rate = (5.0 × 105 L5mol-5s-1)[H2SeO3][I-]^3[H+]^2

The reactant concentrations are:
[H2SeO3] = 1.5 × 10-2 M
[I-] = 2.4 × 10-3 M
[H+] = 1.5 × 10-3 M

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