rate = k(A)^x(B)^y
The problem tells you that the reaction is 1st order with respect to A and zero order with respect to B. The order number is the exponent so x = 1 and y = 0
rate = k(A)^1(B)^0 = k(A)(1) = k(A)
Study the chemical reaction.
A + B ⟶ C + D
A scientist studying this reaction states the reaction is first order with regard to A and zeroth order with regard to B.
What is the rate law for this reaction?
Rate = K [A]
Rate = K [B]
Rate = K [A]^2[B]
Rate = K [A][B]
Can someone walk me through this problem? I'm not sure where to start.
1 answer
1 answer