What is the equilibrium molarity of chloride if 19.6g of CaCl2 (110.984g/mol) is dissolved in water and diluted to 0.500L?

Answer 1

Answer contains three significant figures.

Molarity=moles/Volume (L)

Calculate moles of CaCl2, followed by moles of Cl2:

[19.6g*(1 mole/110.984g)]=-moles of CaCl2

moles of CaCl2*(2 moles of Cl/1 moles of CaCl2)= moles of Cl

moles of Cl/0.500L= molarity of Cl