Determne the boiling point of 16.3g of calcium chloride dissolved in 250. g water.

Question

My work:
16.3 g CaCl2 *(1 mole CaCl2/110.984 g Cacl2)= 0.147 mol CaCl2
M= 0.147/0.250kg =0.588 mCaCl2 ... From here, How do you find out how many ions CaCl2 has. Calcium has a 2+ charge and Cl is - charge. I don't get how together it is 3 ions. I need this piece of info because I need to multiply 0.588 by 3 and I'm not sure how my teacher got 3, and I'm confused. It should = 1.76 M CaCl2.
To find boiling point... I know how to do the rest. I'm just confused on the IONS part. How to determine that?

#2) Another question is similar. Calculate the freezing pt of sol'n that contains 32.7 g of sodium acetate dissolved in 250. g of water. I know how to find the freezing point but the number I'm confused of to figure out my answer is the #of ions. It's supposed to be 2 ions (it's the particle molality)... ... I know Sodium has a + charge and Acetate is a - charge. How is it 2 ions though if it cancels out???

Answer 1

a. CaCl2=3ions; 1 Ca+2, two Ca- ions. Now to find bp, shouldn't you be using molality, not Molarity?
b. Na+ Acetate- ion, two ions.
ions do not cancel out, you need a new brand of wine. Ions are particles, you count them, you dont cancel them out. If you had 100 males, and 100 female, that is 200 persons, they did not cancel out and become couples. Sodium acetate is a couple, but when it dissolves, it is two ions.