well, velocity is a vector so we need to find her displacement vector from start to finish.
1 km in y direction
then .2 cos 45 in negative y direction and .2 sin 45 in negative x direction
so in the end
y = 1 - .141 = .858 km north
x = -.141 or .141 km west
distance from start =sqrt(.858^2+.141^2) = sqrt(.736+.020) =.869 km
time = .25 hr + 160/3600 hr = .25 + .04 = .29 hr
so .869 km/.29 hr = 3 km/hour
direction = tan^-1 (.141/.858) degrees west of north
or 9.23 deg west of north which is 360-9.23 =351 on your compass if all directions given are magnetic not true.
To get to school a girl walks 1 km North in 15 minutes she th
en walks 200metere Southwest in 160 second find her average velocity
4 answers
All angles are measured CW from +y-axis.
V1 = 1000m/900s = 1.11 m/s[0o].
V2 = 200m/160s = 1.25 m/s[225o].
V = 1.11[0o] + 1.25[225o].
V = (1.11*sin0+1.25*sin225) + (1.11*cos0+1.25*cos225)I,
V = -0.884 + 0.226i = 0.912m/s[-90o] = 0.912m/s[270o] CW.
V1 = 1000m/900s = 1.11 m/s[0o].
V2 = 200m/160s = 1.25 m/s[225o].
V = 1.11[0o] + 1.25[225o].
V = (1.11*sin0+1.25*sin225) + (1.11*cos0+1.25*cos225)I,
V = -0.884 + 0.226i = 0.912m/s[-90o] = 0.912m/s[270o] CW.
Answer
graphh is important for these questio
1 answer