Asked by Marie
Two lovers have a spat and swear they will never see each other again. The girl walks due south at 6 mph while the boy walks at 10 mph on a heading of North 60 degrees West. How fast is the distance between them changing 30 minutes later?
Answers
Answered by
Reiny
let the time after their split be t hrs
I see a triangle with sides 10t and 6t and an angle of 120° between them
let the distance between them be d miles
by the cosine law:
d^2 = (6t)^2 + (10t)^2 - 2(6t)(10t)cos120°
= 136t^2 + 60t^2
d2 = 196t^2
d = 14t
dd/dt = 14 mph , a rate independent of the time
check my arithmetic
I see a triangle with sides 10t and 6t and an angle of 120° between them
let the distance between them be d miles
by the cosine law:
d^2 = (6t)^2 + (10t)^2 - 2(6t)(10t)cos120°
= 136t^2 + 60t^2
d2 = 196t^2
d = 14t
dd/dt = 14 mph , a rate independent of the time
check my arithmetic
Answered by
Marie
You don't have to derive anything?
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