henry2,

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Questions

The following questions were asked by visitors named henry2,.

Graph the quadratic functions y = -2x^2 and y = -2x^2 + 4 on a separate piece of paper. Using those graphs, compare and contrast the shape and position of the graphs.

In the courage that my mother had uses a metaphor to characterize the speakers poem. In an essay, describe the comparison the speaker makes, citing details from the poem your point. Then, explain what the comparison tells you about the kind of person the...

Answers

The following answers were posted by visitors named henry2,.

All angles are measured CW from +y-axis. a. cos45 = h/200. h = 141.4 km. sin45 = d1/200. d1 = 141.4 km. Tan60 = d2/141.4. d2 = 245 km. XZ = d1 + d2 = 141.4 + 245 = 386 km. b. YZ^2 = d2^2 + h^2 = 245^2 + 141.4^2 = 80,019, YZ = 283 km[120o] CW. b.

All angles are measured CW from the +y-axis. P = 0o. Q = 90o.

1. V = Vo + g*Tr = 0., 48 + (-32)Tr = 0, Tr36 + = 1.5 s. = Rise time. 2. V^2 = Vo^2 + 2g*h = 0. 48^2 + (-64)h = 0, h = 36 ft. 3. h = 0.5g*Tf^2 = 36 + 160. 16*Tf^2 = 196, Tf = 3.5 s. = Fall time. Tr + Tf = 1.5 + 3.5 = 5.0 s. = Time in air. 4. V = Vo + g*Tf...

r = X km/h in the mornings. r = x-1 km/h in the evening. t1 + t2 = 5 .4 h. x * t1 = 12. t1 = 12/x. (x-1) * t2 = 12. t2 = 12/(x-1). t1 + t2 = 5.4. 12/x + 12/(x-1) = 5.4. 12(x-1) + 12x = 5.4x(x-1), 12x - 12 +12x = 5.4x^2 - 5.4x, 5.4x^2 - 24x - 5.4x + 12 = 0...

Y = 4(x+5)(x-2). = 4(x^2-2x+5x-10), = 4(x^2+3x-10), Y = 4x^2+12x-40. Vertex form: a(x-h)*2 + k. a = 4. h = -B/2A = -12/8 = -3/2. K = 4(-3/2)^2 + 12(-3/2) - 40 = 9 - 18 - 40 = -49. Y = 4(x+3/2)^2 -49. You are correct!! Excellent job!

-13v = 195. V = -15. My answer is D.

7. Add 4 to each side and solve for h. 8. P = $245/35 = 9. Do you mean : 8*2 + 9(12/3x^2) - 7.

Y = 4x^2 = 4*(-2)^2 = 4 * 4 = 16. (-2, 16). My answer is A.

1. Mass = 10cm/5cm * 5kg = 2. k = 35/0.25cm = 3. M*g = 2 * 9.8 = 19.6 N. applied. Spring A: Disp. = 19.6N * 1m/5N = 3.92 m. M*g = 10 * 9.8 = 98 N. applied. Spring B: Disp. = 98N * 1m/9N = 10.9 m.

2. radius = 2 mm = 0.002 meters. A = pi*r^2 = 3.14 * (2*10^-3)^2 = 1.26*10^-5 m^2. R = p*L/A = 2.8*10^-8 * 25/1.26*10^-5 = 0.056 Ohms.

Given: E = 130 Volts. 100v. is too low for the given circuit values. R1 = 3k. R2 = 4k. R3 = 1k, P3 = 200mW. R4 = ? a. P3 = V3^2/R3 = 200. V3^2/1 = 200, V3 = 14.14 volts. I3 = V3/R3 = 14.14/1=14.14 mA = I1 = I2 = I4. b. V4 = E - I(R1+R2+R3) = 130 - 14.14mA...

See your 9:20 PM post.

I = E/7R = 15/7R. V1 = I*R = 15/7R * R = 15/7 = 2.14 Volts. V2 = I*2R = 15/7R * 2R = 30/7 = 4.29 Volts. V3 = I*4R = 15/7R * 4R = 60/7 = 8.57 Volts.

kW =1500/1000 = 1.5. kWh = 1.5 * 5 = 7.5. Cost = 7.5 * 10 = 75 Cents.

The last choice is my answer.

Tan110 = d/X. d = x*Tan110. . Tan150 = d/(x-75). d = (x-75)*Tan150. x*Tan110 = (x-75)*Tan150. x = (x-75)*Tan150/Tan110, x = (x-75)*0.21, x = 0.21x - 15.75, X = -20 Ft. d = x*Tan110 = -20*Tan110 = 55 Ft.

-13V = 195. V = 195/-13 = -15. Check: (-15) * (-13) = +195.

I = V/Rm = 5.70/95 = 0.06A. r = V/I = (6-5.7)/0.06 = 0.30/0.06 = 5. Ohms.

We cannot help you without the required information. Please READ your post.

Change = (22-(-13))/(10-3) = 35/7 = 5oF.

Net Loss = -26 - 11 - 9 + 13 = $33.

b + 7/8 >= 1/6. b >= 1/6 - 7/8, b >= 4/24 - 21/24, b >= -17/24. Do you mean 40 < (5/8)k ? If so: 40 < 5k/8. Multiply both sides by 8: 320 < 5k, 320/5 < 5k/5, 64 < k.

-45/6 + (-13/6) = -58/6 = -29/3.

Multiplying Eq2 and Eq3 by 3 won't help, because it does not eliminate a variable. Yes, you can use Eq1 and Eq3 and then Eq2 and Eq3. Eliminate X in each case. .

Eq1: 2x - 5y + 3z = 8. Eq3: 2x + 6y + 4z = -6.(multiplied by 2). Diff. = -11y - z = 14. Eq2: 3x - y + 4z = 7. Eq3: 3x + 9y + 6z = -9.(been multiplied by 3). Diff. = -10y - 2z = 16. -22y - 2z = 28.(been multiplied by 2). -10y - 2z = 16. Diff. = -12y = 12,...

You are welcome!

You are welcome!

31 - 10 = 21 People to sit on blankets. Can you finish it?

17ft + (6/12)ft = 17 + 1/2 = 17.5 Ft.

(-3, 16), (15, -8). X = (15-(-3)) = 18. Y = (-8-16) = -24. d = sqrt(X^2 + Y^2) =

sin A = 1/2 = Y/r. Cos A = sqrt3/2 = X/r. x = sqrt 3, Y = 1, r = 2. Tan A = Y/X = 1/sqrt3. Cot A = 1/Tan A = sqrt3/1 = sqrt 3. sec A = 1/Cos A = 2/sqrt 3. csc A = 1/sin A = 2/1 = 2.

water/flour = 6/4 = 3/2. a. 3/2 = W/6. 2W = 18, W = 9 cups of water. b. 3/2 = 2/F. 3F = 4, F = 4/3 = 1 1/3 cups of flour.

Yes, who is Barbara's competitor? How fast does he/she walk?

F(x) = 4x^2 - 12x + 13. h = -B/2A = 12/8 = 3/2. K = 4(3/2)^2 - 12(3/2) + 13 = 9 - 18 + 13 = 4. Vertex Form: F(x) = a(x-h)^2 + k. = 4(x - 3/2)^2 + 4.

31 - 21 = 21 people to sat on blankets. 21people * 1blanket/3people = 21 * 1/3 = 7 blankets needed.

sqrt a^4 = a^2. Sqrt 169 = 13. solution: (a^2 - 13)^2. check: (a^2 - 13)^2 = a^4 - 26a^2 + 169.

sin40 = d/200. d = 200*sin40.

Function Q: (4, 0), m = 1/4. Y = mx + b. 0 = (1/4)4 + b, b = -1 = y-int. Eq: Y = (1/4)x - 1. Function R: (x, y): (-4, 14), (3, 0), (5, -4). m = (0-14)/(3-(-4)) = -14/7 = --2. Y = mx + b, 14 = -2*(-4) + b. b = 6 = y-int. Eq: Y = -2x + 6.

2cups * 8oz/cup = 16 oz. = 16 oz./bottle. 16oz./bottle * 5bottles = 80 oz. of juice. 1qt. = 32 oz. of juice.

2L = 2,000 mL. 2000mL/250mL = 8 glasses.

|2x| > |2x-5| + |x+1|. 2x > 2x-5 + x+1. 2x -2x - x > -4, -x > -4, X < 4. Reversed inequality sign after dividing by -1.

43/10 - n = 4. n = 43/10 - 4 = 43/10 - 40/10 = 3/10.

3/10 pizza for each friend.

Parker Music: $40/h Joelle Music: $25/0.5h = $50./h. 50 - 40 = $10 more per h.

5/6/(1/3) = 5/6 * 3/1 = 15/6 = 2 3/6 = 2 1/2 servings. A half serving = 1/2 * 1/3 = 1/6 cup.

6/(2/3) = 6 * 3/2 = 18/2 = 9 Loaves.

B = 180 - (35+65) = 80o. AB/sin65 = 6/sin80. AB = 6*sin65/sin80 = 5.52 cm BC/sin35 = 6/sin80. BC = ?

r = d/t = 792mi/125min. = 6.336 mi/min. d = r*t = 6.336 * 30 =

P*r*t = I. 250 * r * 3 = 30. 750r = 30, r = 0.04 = 4%.

Troyan is X yrs. old. Tyshai is 7x yrs. old. 5 yrs. Later: (x+5) + (7x+5) = 98. X =

Alex has X jelly beans. x - 2x/5 = 3x/5 remaining. 1/3 * 3x/5 = 3x/15 = x/5 remaining. x/5 = 51. X = 255. Martha ate 2/3 * 3x/5 = 2/3 * (3*255)/5 = 102 Jelly beans. 102/255 = 34/85 = 2/5 of original jelly beans.

sqrt(-50x^2y^2) = sqrt(25*2*(-1)x^2y^2) = 5i(xy)sqrt(2). Note: sqrt 25 = 5, sqrt (-1) = i, 2 remains under radical.

b. (8, -98) is NOT a solution. (8, -99) IS a solution.

V = Vo - Vo*r*T = $42,000. 150,000 - 150,000*r*9 = 42,000. 1 - 9r = 0.28, 9r = 0.72, r = 0.08/yr. = Annual depreciation rate. V = Vo - Vo*r*T. V = 150,000 - 150,000*0.08*4 = $102,000.

All angles are measured CW from +y-axis. d = 20km[205o] - 30km[60o]. X = 20*sin205 - 30*sin60 = -34.43 km. Y = 20*Cos205 - 30*Cos60 = -33.13 km. d = sqrt(X^2 + Y^2).

360-316 = 44o W. of N. Cos44 = h/505. h = 363 km. Cos A = 363/770. A = 62o W. of S. = 242o CW from +y-axis = Bearing(Heading) from Elgin to Canton.

M*g = 1800 * 9.8 = 17,640 N. = Wt. of vehicle = Normal force, Fn. u*Fn = 0.7 * 17,640 = 12,348 N. = Force of kinetic friction. -uFn = M * a. -12,348 = 1800 * a. a = -686 m/s^2. V^2 = Vo^2 + 2a*d = 0. 25^2 + (-13.72)d = 0, d = 45.6 m.

Y = Ax^2 + Bx + C. C = -4.6 * 2 = -9.2. B = -4.6 + 2 = -2.6. h = (-2 + 4.6)/2 = 1.3. h = -B/2A = 1.3. 2.6/2A = 1.3, A = 1. Eq: Y = x^2 - 2.6x - 9.2.

Note: The given x-int. satisfy my Eq., but my y-int. is -9.2 instead of 1.5.

16t^2 = 10,000. t = 25 s. d = 300mi/h * (25/3600)h =

As = 2*(W*h) + 2*(L*h) + 2*(L*W). As = 2*(5*7) + 2*(14*7) + 2*(14*5) =

They gave you the Eq and the dimensions; what do you need?

Given: r1(3, 0), r2(7, 0). y-int.(0, -21). V(5, 4). Y = a(x-h)^2 + k. a(3 - 5)^2 + 4 = 0, 4a = -4, a = -1. Vertex form: Y = -1(x - 5)^2 + 4. Y = -1(x^2 - 10x + 25) + 4, Y = -x^2 + 10x - 21(Standard form).

V = Vo + a*t = 0 + 328*1.5 =

1. Y = 20 + 0.02x. Y = 15 + 0.03x. x = minutes used. 2. 15 + 0.03x < 20 + 0.02x. 3. 0.03x - 0.02x < 20 - 15, 0.01x < 5, X < 500 minutes.

P(-8, -10), m = -4. Y = mx + b. -10 = -4*(-8) + b, Y = -4x - 42.

Total females = 23 + 32 +16 +18 = 89. Total males = 30 + 26 + 12 + 21 = 89 Total students = 178. A. 32/89 * 100% = 36%. B. 30/89 * 100% = C. (18+21)/178 * 100% = .

A. Acute: An angle that measures < 90o. B. Right: An angle that measures 90o. C. Obtuse : An angle that is > 90o but < 180o. D. Straight: An angle that measures 180o.

T = (1/5 + 1/3) * 11/4 = (3/15 + 5/15) * 11/4 = 8/15 * 11/4 = 88/60 = 1.5 h.

4. 3x^2 = 27. x^2 = 9, X = 3, and -3.

1. Y = -x^2 + 1. Opens downward. y-int. = (0, 1). h = Xv = -B/2A = 0/-2 = 0 = axis of symmetry. k = Yv = -0^2 + 1 = 1. V(h, k) = V(0, 1). Y = x^2. Opens upward. y-int. (0, 0). h = Xv = -B/2A = 0/2 = 0 = axis of symmetry. k = Yv = 0^2 = 0. V(0, 0). 2. Y =...

Cir. = pi * 2r = 3.14 * 0.56 = 1.76 m. Va = 22m/s * 6.28rad/1.76m = 78.5 rad/s. V = Vo + a*t = 78.5. 0 + a*9 = 78.5, a = 8.72 rad/s^2.

V = 10km/h = 10,000m/3600s = 2.78 m/s. Cir. = pi * 2r = 3.14 * 14 = 44.0 m. Va = 2.78m/s * 6.28rad/44m = 0.40 rad/s.

3. V = Vo + g*t = 0. 24 + (-32)t = 0, t = 0.75 s. h = ho + Vo*t + 0.5g*t^2 = 50 + 24*0.75 + (-16) * 0.75^2 = 5. Use Quadratic Formula.

6. 3x^2 + 4x - 7 = 0. h = Xv = -B/2A = -4/6 = -2/3. k = Yv = 3(-2/3)^2 + 4(-2/3) - 7 = If k is > 0, No real solution. If k is = 0, 1 solution. If k is < 0, 2 solutions. 8. pi * r^2 = 12. 3.14 * r^2 = 12, r = ? 9. Y = x^2 + 9. Y = 6x. In Eq1, replace Y wit...

KE = PE. 0.5*M*V^2 = M*g*h, Divide both sides by 0.5M: V^2 = 2g*h = 19.6 * 0.85 = 16.66, V = 4.1 m/s. @ bottom of incline. h = 0.5g*t^2 = 1 m. 4.9t^2 = 1, t = 0.45 s. d = Vx * t = 4.1 * 0.45 =

a. 15rad/s * 4s = rad. b. V = Vo + a*t = 5 + 2.5*4 = rad/s.

V = L*W*h = 7 * 4 * 3 = cubic inches.

2. 700grams/454 = 1.54 Lbs. = 24.7 ozs. So the answer is B or C. I chose C.

Width = W. Length = 4W. Area = W * 4W = 900 cm^2. W * 4W = 900. W = ? w

The 1st integer = X. The 2nd integer = x - 2. x^2 + (x-2)^2 = 34. x^2 + x^2 - 4x + 4 = 34, 2x^2 - 4x + 4 = 34, 2x^2 - 4x - 30 = 0, x^2 - 2x - 15 = 0, -15 = -5 * 3. sum = -5 +3 = -2 = B. (x-5)(x+3) = 0, x - 5 = 0. X = 5. x + 3 = 0. X = -3. X = 5(chose posi...

9.4*10^-7. The -7 means that you move the decimal 7 places to the left to return to standard form.

Given: M1 = 591kg, V1 = 7.3m/s. M2 = ?, V2 = 0? Vf = 4.7m/s = Velocity of M1 and M2 after collision. a. p1 = M1*V1 = 591 * 7.3 = 4314. b. p before = p after. M1*V1 + M2*V2 = M1*Vf + M2*Vf. 4314 + M2*0 = 591*4.7 + M2*4.7 4314 = 2778 + 4.7M2, M2 = 327 kg. c...

d. Given: M1 = 591 kg, V1 = 7.3 m/s. M2 = 327 kg, V2 = -5.5 m/s. Vf = ? p before = p after. M1*V1 + M2*V2 = M1*Vf + M2*Vf. 4314 + 327 * (-5.5) = 591*Vf + 327*Vf, Vf = ?

A + B = 250g[0o] + 150g[120o]. X = 250 + 150*Cos120 = 175 Grams. Y = 150*sin120 = 130 grams. 175 + 130i = 218g[36.6o] CCW. Tan A = Y/X. The magnitude and direction of C for equilibrium = 218g[36.6+180] = 218g[216.6] CCW.

V = Vo + a*t = 0 + 2*4 = 8 m/s. = Final velocity. V^2 = Vo^2 + 2a*d = 8^2. 0 + 4*d = 64, d = 16 m.

I = P*r*t = 300*0.05*7 = $105.

Sorry! my mistake.

A. x^2 + 49 = 0. x^2 = -49. X = sqrt (-49) = sqrt(49*(-1)) = 7i. No real solution. B. (x+7i)(x-7i).

V = L * W * h = 480 in^3. L * 6 * 10 = 480, L = ?

Width(breadth) = W. Length = 3w + 10. Length = 3w+10 - 50 = 3w - 40. Width = w + 4. 3w - 40 = 2(w + 4). W = 48 m. Width = w + 4 = 48 + 4 = 52 m. Length = 2 * 52 = 104 m.

Subtract Eq2 from Eq1: x + y = 7. x + 2y = 11. Diff. = -y = -4, Y = 4. In Eq1, replace Y with 4 and solve for X: x + 4 = 7.

$5.67/18 = $0.315/carton. $0.315/carton * 6cartons = $1.89.

Cir. = pi * 2r = 3.14 * 84 = 263.8 cm. 66cm * 1rev/263.8cm = 0.25 = 1/4 rev.

Given: M1 = 2 kg, V1 = 10 m/s. M2 = 3 kg, V2 = 0. V3 = Velocity of M1 and M2 after collision. p before = p after. M1*V1 + M2*V2 = M1*V3 + M2*V3. 2 * 10 + 3 * 0 = 2*V3 + 3*V3, V3 = m/s.

ZX = 5/2 * NL. A similar problem says that triangle LMN has sides of 5 and 3. So ZX = 5/2 * 5 = 12.5 units. Or ZX = 5/2 * 3 = 7.5 units.

V = Vo + a*t = 2200 + 1000*10 = 12,200 ft/s.