Ask a New Question
Search
Questions and answers by
henry2,
Answers (592)
Bulbs = 2^n * 3. n = the number of years. 1st year: 2^1 * 3 = 6 bulbs. 2nd year: 2^2 * 3 = 12 bulbs. 3rd year: 2^3 * 3 = 24 bulbs. 8th year: 2^8 * 3 = 768 bulbs.
You are welcome.
F(x) = -(x+2)^2 + 6 F(x) = -(x^2+4x+4) + 6 -x^2-4x-4 + 6 = 0. -x^2 - 4x + 2 = 0. Use quadratic formula.
Tan18 = 5/x X = 15.4 m.
P = Po + Po*r*T = 1250 + 1250*0.0425*4 =
5+2 =
correction: -32 1/3 + x = 30 -97/3 + x = 30
C0rrection: -32 1/3 + x = 30 -97/3 + x = 30 x =
-32 1/3 + x = 30. -96/3 + x = 30. x =
-32 + x = 30. x =
o.7m = 77 m =
29029Ft * 1m/3.3Ft. =
Wf = 8Lbs/gal. Wa + 8x = Wt Wa + 8*14 = 2091 Wa = 1979 Lbs. = weight of airplane without fuel. Wa + 8x = 1979 + 8*50 =
V1*T + V2*T = 216 95T + 85T = 216. T =
Po + 0.38Po = $621,000. Po =
You are welcome.
V^2 = 150^2 + 50^2 V =
Original photo = 4-1n. by 6-in. enlarged photo = 16-in by 24-in. a. Ratio = 6:24. b. 6:24 = 1:4.
V * T = 400 V * 1.16 = 400 V =
As = (L*W)*2 + (L*h)*2 + (W*h)*2 As = (12*5)*2 + (12*4)*2 + (5*4)*2 = __m^2.
h = 8Ft./in * 5.5in. = 44 Ft.
Check: E = 31.8[-58] + 233.7[32] + 182.9[-148] E = (31.8*cos(-58)+233.7*cos32+182.9*cos(-148)) + j(31.8*sin(-58)+233.7*sin32+182.9*sin(-148) E = 59.93 - j0.048 = 59.9300192V[0.046o]. The voltage across L and C is greater than 60 volts, but the vector sum
Correction: Vr = 31.8V. NOT 31.8A.
Given: R = 20 ohms, L = 390 mH(0.39h), C = 23 uF(23*10^-6Farads). E = 60V.rms? @ 60 Hz. Xl = 2pi*F*L = 6.28*60*0.39 = j147 ohms. Xc = 1/(2pi*60*23*10^-6) = -j115.3 ohms. Z = R + j(Xl-Xc) = 20 + j(147-115 ) = 20 + j32 = 37.7 ohms[58o]. I = E/Z =
2 * 6 = 12.
All angles are measured CW from +y-axis. AB = 5km/h * 2h = 10km[46o]. BA = 10km[46+180] = 10km[ 226o]. AC = 9km/h * 2h = 18km[127o]. BC = distance between the ships after 2h. BC = BA+AC = 10[226] + 18[127] BC = (10*sin226+18*sin127) +
k = F/d = 0.8N./0.02m = 40N/m.
incomplete.
V = pi*r^2*h. r = 34/2.
Check: E = 12 + 0.027i = 12.0000304V[0.128o]. The magnitude of Vc and Vl is greater than the supply voltage, but the vector sum = the 12V.-supply as it should.
Xl = 2pi*F*L = 6.28*1400*0.0057 = j50 ohms. Xc = 1/(2pi*F*C) = 1/(6.28*1400*3.8*10^-6) = -j30 ohms. Z = R + j(Xl-Xc) = 15 + j(50-30) = 15 + j20 = 25 ohms[53o]. I = E/Z = 12/25[53o] = 0.48A[-53o]. The current lags the voltage by 53o. a. Vr = I*R = 0.48[-53]
You are welcome.
All angles are measured CW from +y-axis. RP = 50[35o] * 4 = 200km[35o]. PR = 200[35+180] = 200km[215o]. RQ = 40[205o] * 4 = 160km[205o]. PQ = PR+RQ = 200[215o] + 160[205o] PQ = (200*sin215+160*sin205) + (200*cos215+160*cos205)I PQ = -182. - 309i. =
x^2-18x+81 = 0. 81 = -9*-9. (-9)+(-9) = -18 - B. (x-9)(x-9) = 0 x-9 = 0, X = 9. Only one solution.
a. RC = 5*10^6 * 6*10^-6 = 30 s. Vr = 12/e^x = 9 e^x = 12/9 = 1.333 X = 0.288 = t/RC. t/30 = 0.288 t = 8.63 s. b. Xc = 1/(2pi*F*C) = 1/(6.28*60*6*10^-6) = 442 ohms. Z = 5*10^6 - j442 = 5*10^6 0hms. I = E/Z = 12/(5*10^6) = 2.4*10^-6 A = 2.4 uA.
correct. The value of Y for all points on the x-axis is zero.
3/6 = x/96 X = 48.
L*W*h = 60 L*W*3 = 60 L*W = 20 m^2 = area of the floor.
Xc = Xl = 2pi*F*L = 6.28*4100*0.32 = 8244 ohms. C = 1/(2pi*F*Xc) = 1/(6.28*4100*8244) = 4.7*10^-9 farads = 0.0047 uF.
a. W = F*d = 25 * 10 = 250 J. b. Fp = 125*sinA = 25 = Force parallel with incline. sinA = 25/125 = 0.20, A = 11.5o. sin11.5 = h/10 h = 10*sin11.5 =
x^2+y^2 = r^2 30^2 + y^2 = 50^2. Y = ht. of kite.
eff. = L/(E*Vr) = 160/(25*8) = 0.80 = 80%.
x^2+4x-5 = 0. -5 = -1*5. -1+5 = 4 = B. (x-1)(x+5) = 0 x-1 = 0, X = 1. x+5 = 0, X = -5.
1.5/e^x = 1.0 e^x = 1.5 X = 0.405 = t/RC. RC = 3.9*5 = 19.5 milliseconds. t/19.5 = 0.405 t = 7.91ms.
5/5-3/5 = 2/5 left. 2m/5 = 12 m = $30 = the original amt. 3/5 * 30 = $18 = amt. spent on gifts. Joan's gift: $x. Luann's gift: $3x. x+3x = 18 X = $4.50. 3x = $13.50.
(3/7)x = 5/6 Multiply both sides by 7/3. X = 7/3 * 5/6 = 35/18 = 1.94 Lbs.
(1/2)/3 = 1/2 * 1/3 = 1/6 0f the half candy bar. 2 * 1/6 = 2/6 = 1/3 of the whole candy bar.
V^2 = Vo^2 + 2g*h = 0 + 19.6*5*10^5 = 9.8*10^6 V = sqrt (9.8*10^6) = ___ m/s.
x^2-8x+12 = 0. 12 = -2*(-6). -2 + (-6) = = -8 = B. (x-2)(x-6) = 0 x-2 = 0, X = 2. x-6 = 0, X = 6. roots: (2, 0), (6, 0). Y-int. = (0,12). (8,12). h = -B/2A = 8/2 = 4. k = 4^2-8*4 + 12 = -4. V(h, k) = V(4, -4). Graph: (0,12), (2,0), V(4,-4), (6,0), (8,12).
Tan21 = 450/x X = 1172 Ft. = hor. distance between bldg. and tower. Tan24 = h1/1172 h1 = 1172*Tan24 = 522 Ft. ht. = 522 + 450 =
