Let me write you a process to follow. Copy this. It will work almost all of your stoichiometry problems.
1. Write and balance the equation.
C + O2 ==> CO2
2. Convert what you have into mols.
mols = grams/atomic mass
7.10/12 = about 0.6 but you need a better answer than that estimate.
3. Using the coefficients in the balanced equation, convert mols C to mols of the product (CO2).
0.6 mols C x (1 mol CO2/1 mol C) = 0.6 x 1/1 = 0.6 mols CO2
4. Now convert mols CO2 to grams.
g = mols x molar mass = about 0.6 x 44 = about 26 g. This is the theoretical yield (TY)
5. The actual yield from the problem is 12.25 (AY)
% yield = (AY/TY)*100 = ?
Remember to rework this from the beginning. My numbers are just estimates.
the reaction of 7.10g carbon with excess O2 yields 12.25g of CO2. what is the percent yield of this reaction?
I have tried everything and looked through all of my notes and nothing is working for stiochiometry
3 answers
Thanks! this helped so MUCH! :)
The reaction of 7.95 g of carbon with excess O2 yields 12.1 g of CO2. What is the percent yield of this reaction?