The reaction of 9.58 g of Carbon with excess O2 yields 8.90 g of CO2, what is the percent yield of this reaction?

Answer 1

C + O2 ==> CO2
mols C = g/atomic mass C = estimated 0.3
mols CO2 = 0.3 since there is 1 mol CO2 for each mol C.
g CO2 = mols CO2 x molar mass CO2 = ? and that is the theoretical yield (TY). The problem tells you the actual yield is 8.90g.
%yield = [AY/TY]*100 = ?

Answer 2

98