C + O2 ==> CO2
mols C = grams/molar mass
1 mol C forms 1 mol CO2
Then grams CO2 = mols CO2 x molar mass CO2. This is the theoretical yield.
%yield = (actual yield/theo yield)*100 = ?
the reaction of 6.62g of carbon with excess oxygen yields 13.40g of CO2. what is the percent yield of this reaction
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