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The 5th term in a geometric system is 160. The 7th term is 40. What are the possible values of the 6th term in the sequence?Asked by slayrat
The 5th term in a geometric sequence is 120. The 7th term is 30. What are the possible values of the 6th term of the sequence?
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Answered by
Bot
Let's call the first term of the sequence "a" and the common ratio "r". We can use the formula for the nth term of a geometric sequence to set up two equations:
a * r^4 = 120 (since the 5th term is a * r^4)
a * r^6 = 30 (since the 7th term is a * r^6)
Now we can solve for "a" and "r". One way to do this is to divide the second equation by the first:
(r^6)/(r^4) = 30/120
Simplifying, we get:
r^2 = 1/4
Taking the square root of both sides, we get:
r = +/- 1/2
Now we can substitute these values of "r" back into either equation to solve for "a". Let's use the first equation:
a * (1/2)^4 = 120
Simplifying, we get:
a = 960
So our possible sequences are:
960, 480, 240, 120, 60, 30, ...
or
960, -480, 240, -120, 60, -30, ...
Therefore, the possible values of the 6th term of the sequence are 60 and -30.
a * r^4 = 120 (since the 5th term is a * r^4)
a * r^6 = 30 (since the 7th term is a * r^6)
Now we can solve for "a" and "r". One way to do this is to divide the second equation by the first:
(r^6)/(r^4) = 30/120
Simplifying, we get:
r^2 = 1/4
Taking the square root of both sides, we get:
r = +/- 1/2
Now we can substitute these values of "r" back into either equation to solve for "a". Let's use the first equation:
a * (1/2)^4 = 120
Simplifying, we get:
a = 960
So our possible sequences are:
960, 480, 240, 120, 60, 30, ...
or
960, -480, 240, -120, 60, -30, ...
Therefore, the possible values of the 6th term of the sequence are 60 and -30.
Answered by
Bot
I apologize for the mistake in my previous response. The correct solution is as follows:
Using the same approach as before, we can set up the equations:
a * r^4 = 120
a * r^6 = 30
Dividing the second equation by the first, we get:
r^2 = 1/4
Taking the square root, we get:
r = +/- 1/2
Substituting each value of "r" into the first equation to solve for "a", we get:
When r = 1/2:
a = 120 / (1/2)^4 = 1920
When r = -1/2:
a = 120 / (-1/2)^4 = -1920
Therefore, the two possible sequences are:
1920, 960, 480, 240, 120, 60, ...
and
-1920, -960, -480, -240, -120, -60, ...
And the possible values of the 6th term are 60 and -60. I apologize for any confusion caused by my previous response.
Using the same approach as before, we can set up the equations:
a * r^4 = 120
a * r^6 = 30
Dividing the second equation by the first, we get:
r^2 = 1/4
Taking the square root, we get:
r = +/- 1/2
Substituting each value of "r" into the first equation to solve for "a", we get:
When r = 1/2:
a = 120 / (1/2)^4 = 1920
When r = -1/2:
a = 120 / (-1/2)^4 = -1920
Therefore, the two possible sequences are:
1920, 960, 480, 240, 120, 60, ...
and
-1920, -960, -480, -240, -120, -60, ...
And the possible values of the 6th term are 60 and -60. I apologize for any confusion caused by my previous response.
Answered by
Bot
Yes, that is correct. I apologize for any mistakes in my previous responses.
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