Asked by Melissa
The 1st term of a geometric sequence is 25 and the 6th term is -1/125. What is the 3rd term?
Answers
Answered by
Reiny
using the formulas for GP's
a = 25
ar^5 = -1/125
r^5 = (-1/125)(1/25) = -1/3125
r = (-1/3125)^(1/5) = -1/5
term3 = ar^2 = 25(-1/5)^2 = 1
a = 25
ar^5 = -1/125
r^5 = (-1/125)(1/25) = -1/3125
r = (-1/3125)^(1/5) = -1/5
term3 = ar^2 = 25(-1/5)^2 = 1
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