Asked by Siphosethu
Which term of the Geometric sequence with first two terms 192 and 96 is equal to 3
Answers
Answered by
mathhelper
a = 192
r = 96/192 = 1/2
term(n) = a r^(n-1)
3 = 192 (1/2)^(n-1)
1/64 = (1/2)^(n-1)
(1/2)^6 = (1/2)^(n-1)
n-1 = 6
n = 7
It is the 7th term
check:
term(7) = a r^6
= 192 (1/2)^6 = 192(1/64) = 3
r = 96/192 = 1/2
term(n) = a r^(n-1)
3 = 192 (1/2)^(n-1)
1/64 = (1/2)^(n-1)
(1/2)^6 = (1/2)^(n-1)
n-1 = 6
n = 7
It is the 7th term
check:
term(7) = a r^6
= 192 (1/2)^6 = 192(1/64) = 3
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